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To calculate the mass/volume percent composition (% m/v) of a solution, we use the following formula:

\[
\text{% (m/v)} = \left( \frac{\text{mass of solute (g)}}{\text{volume of solution (mL)}} \right) \times 100
\]

From the problem:
- The mass of CH₃OH (methanol) = 23.3 g
- The volume of the solution = 49.0 mL

Substituting these values into the formula:

\[
\text{% (m/v)} = \left( \frac{23.3}{49.0} \right) \times 100
\]

\[
\text{% (m/v)} = 47.55\%
\]

Since the values given (23.3 g and 49.0 mL) have 3 significant figures, we round the result to 3 significant figures:

\[
\text{% (m/v)} = 47.6\%
\]

Thus, the mass/volume percent composition of the solution is **47.6%**.

Would you like more details or have any questions? Here are some related problems:

1. How would the % (m/v) change if the volume of the solution increased but the mass stayed the same?
2. How do you calculate % (m/m) composition if the solution is measured in grams?
3. What is the difference between % (m/v) and % (v/v)?
4. How would temperature affect the % (m/v) composition?
5. What is the effect of dilution on the % (m/v) of a solution?

**Tip**: Always ensure that your final answer has the same number of significant figures as the least precise value in the given data.

Calculate the mass/volume percent composition, or % (mass/volume), of 49.0 mL of solution containing 23.3 g of CH₃OH. Be sure your answer has the correct number of significant figures.

Learn how to calculate the mass/volume percent composition for a solution containing 23.3 g of CH₃OH in 49.0 mL of solution. The calculation includes the correct significant figures and fundamental concepts related to solution composition. Suitable for Grades 10-12.

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