Math Problem Statement

A solution is prepared by dissolving 3.6 g of methanol  (CH3OH,  Molar mass = 32.04g/mol) into water and form 100 mL solution.  Calculate the molarity of Methanol in this solution

Solution

To calculate the molarity of methanol in the solution, we use the formula:

Molarity (M)=moles of solutevolume of solution in liters\text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}}

Step 1: Calculate the moles of methanol

The moles of methanol can be calculated using its mass and molar mass:

moles of methanol=mass of methanolmolar mass of methanol=3.6 g32.04 g/mol\text{moles of methanol} = \frac{\text{mass of methanol}}{\text{molar mass of methanol}} = \frac{3.6\text{ g}}{32.04\text{ g/mol}}

moles of methanol0.1123 mol\text{moles of methanol} \approx 0.1123 \text{ mol}

Step 2: Convert the volume of the solution to liters

Since the solution is 100 mL, we convert it to liters:

volume in liters=1001000=0.100 L\text{volume in liters} = \frac{100}{1000} = 0.100 \text{ L}

Step 3: Calculate the molarity

Now, substitute the moles of methanol and the volume of the solution into the molarity formula:

Molarity=0.1123 mol0.100 L=1.123 M\text{Molarity} = \frac{0.1123 \text{ mol}}{0.100 \text{ L}} = 1.123 \text{ M}

Thus, the molarity of methanol in the solution is 1.123 M.

Would you like further details or explanations on any step? Here are five related questions you might find helpful:

  1. What is the difference between molarity and molality?
  2. How would you calculate the molarity if the volume of the solution changes?
  3. What are other methods to express concentration besides molarity?
  4. How do temperature changes affect molarity?
  5. What is the significance of molar mass in chemical calculations?

Tip: Always make sure the volume is in liters when calculating molarity, as this unit ensures consistency.

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Math Problem Analysis

Mathematical Concepts

Stoichiometry
Molarity Calculation
Unit Conversion

Formulas

Molarity (M) = moles of solute / volume of solution in liters
Moles of solute = mass of solute / molar mass

Theorems

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Suitable Grade Level

Grades 10-12