https://file.aiquickdraw.com/mathbot/file/1729195803231r0cfsrwn.jpg

To solve this problem, we need to calculate the volume percent of acetone in the mixture.

### Given:
- Volume of acetone = 210 mL
- Volume of toluene = 0.53 L = 530 mL (since 1 L = 1000 mL)
- Final solution volume = 0.762 L = 762 mL

### Formula for Volume Percent (\(v/v\)):
\[
\text{Volume Percent} = \left( \frac{\text{Volume of Solute}}{\text{Volume of Solution}} \right) \times 100
\]

In this problem, the solute is acetone, and the solution is the combined acetone and toluene mixture.

### Calculation:
\[
\text{Volume Percent of Acetone} = \left( \frac{210 \, \text{mL}}{762 \, \text{mL}} \right) \times 100
\]
\[
= \left( \frac{210}{762} \right) \times 100
\]
\[
\approx 27.55\%
\]

### Significant Figures:
- The volumes given (210 mL, 0.53 L, and 0.762 L) suggest that the final answer should be rounded to 3 significant figures.

Thus, the volume percent of acetone is approximately **27.6%**.

Would you like more details or have any questions?

### Related Questions:
1. How do you convert volumes between mL and L?
2. What is the significance of significant figures in calculations?
3. How does the density of a substance affect calculations if mass is involved instead of volume?
4. How do you calculate the volume percent of a solution if only the masses are given?
5. What other methods are used to express concentration in solutions?

### Tip:
When mixing solutions with different volumes, ensure you use the total volume of the mixture (not just the sum of the individual volumes) if the question provides a specific final volume.

Suppose 210 mL of acetone and 0.53 L of toluene are mixed, and the final solution has a volume of 0.762 L. Note that the density of acetone is 0.78 g/mL. Calculate the volume percent of acetone in this solution. Be sure your answer has the right number of significant digits.

Learn how to calculate the volume percent of acetone in a solution of acetone and toluene. Given the final solution volume of 0.762 L, acetone volume of 210 mL, and toluene volume of 0.53 L, this problem involves unit conversion and significant figures. Suitable for students in Grades 10-12.

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