A soup factory used 8.26 kilograms of lentils to make 97 tins of soup. To the nearest tenth of a kilogram, how many kilograms of lentils did the factory put in each tin?

To find out how many kilograms of lentils were used per tin, you need to divide the total amount of lentils by the number of tins:

\[
\text{Lentils per tin} = \frac{8.26 \text{ kg}}{97 \text{ tins}}
\]

Now, let's calculate:

\[
\frac{8.26}{97} \approx 0.0852 \text{ kg}
\]

Rounding 0.0852 kg to the nearest tenth of a kilogram:

\[
\text{Rounded result} = 0.1 \text{ kg}
\]

So, the factory put approximately **0.1 kilograms** of lentils in each tin.

Would you like more details or have any questions?

Here are five related questions:
1. How many kilograms of lentils are needed to produce 200 tins of soup?
2. If the factory used 15.5 kilograms of lentils, how many tins could they produce?
3. What would be the cost per tin if lentils cost $2.50 per kilogram?
4. How many tins can be made with 50 kilograms of lentils?
5. If the recipe changes to use 0.15 kilograms of lentils per tin, how many tins can be made from 8.26 kilograms?

**Tip:** When rounding numbers, consider the digit immediately after the place you're rounding to—if it's 5 or higher, round up.

Discover how many kilograms of lentils were used per tin in soup production. This math problem involves dividing 8.26 kilograms of lentils by 97 tins and rounding to the nearest tenth. Ideal for students in Grades 4-6.

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