https://file.aiquickdraw.com/mathbot/file/17266188867876mm6ld62.jpg

Let's solve both problems presented in the image:

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### Problem 9:
The power rating \( P \) is given by the formula:

\[
P = I \times V
\]

where:
- \( P \) is the power in watts,
- \( I \) is the current in amperes (30 amps),
- \( V \) is the voltage in volts (115 volts).

Substitute the given values into the formula:

\[
P = 30 \, \text{amps} \times 115 \, \text{volts}
\]

Let's calculate that:

\[
P = 30 \times 115 = 3450 \, \text{watts}
\]

So, the wattage required in the kitchen is **3450 watts**.

---

### Problem 10:
The equation given is:

\[
S = rx + sx
\]

You need to solve this for \( x \). First, factor out \( x \) from the right-hand side:

\[
S = x(r + s)
\]

Now, divide both sides by \( (r + s) \) to isolate \( x \):

\[
x = \frac{S}{r + s}
\]

So, the solution for \( x \) is:

\[
x = \frac{S}{r + s}
\]

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Would you like more details or have any other questions?

Here are 5 related questions for you:
1. How is electrical power affected by changes in current or voltage?
2. What is the relationship between watts, volts, and amperes?
3. How would you calculate power if the voltage was unknown?
4. What happens to power if the current is halved?
5. How can factoring be used to solve linear equations?

**Tip:** Always double-check units when working with physical quantities like power, voltage, and current to ensure consistency.

The power rating P, in watts, of an electric appliance is determined by P = I * V, where I is the current in amperes, and V is the voltage, measured in volts. If a kitchen requires 30 amps of current and the voltage in the house is 115 volts, what is the wattage of the kitchen?

Learn how to calculate the electrical power in watts for a kitchen using the formula P = I * V. This problem involves a kitchen that requires 30 amps of current and has a voltage of 115 volts, resulting in a power calculation.

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