The horizontal value for the following 60 m [N 20 E] is...

To calculate the horizontal (or eastward) component of the vector given in the form **60 m [N 20° E]**, we can break the vector down into its horizontal and vertical components. The vector makes an angle of **20°** with the north direction, moving eastward.

### Horizontal Component Calculation:

The horizontal component of the vector is found using the cosine of the angle:
\[
\text{Horizontal component} = \text{magnitude} \times \cos(\theta)
\]
where:
- Magnitude = 60 m
- \( \theta = 20^\circ \)

\[
\text{Horizontal component} = 60 \times \cos(20^\circ)
\]

Let me calculate that for you.

The horizontal (eastward) component of the vector **60 m [N 20° E]** is approximately **56.38 m**.

Would you like more details or have any questions? 

Here are some related questions you might consider:
1. What is the vertical (northward) component of the vector?
2. How would you calculate the magnitude of the resultant vector if given both components?
3. What would the horizontal component be if the angle was increased to 30°?
4. How do we calculate the angle between two vectors?
5. How do trigonometric functions like cosine apply to vector decomposition?

**Tip:** To decompose a vector, always use cosine for the horizontal component (if angle is measured from the vertical axis) and sine for the vertical component.

The horizontal value for the following 60 m [N 20° E] is...

Learn how to calculate the horizontal (eastward) component of a vector with a magnitude of 60 m and an angle of 20° from the north. This solution involves using trigonometric functions to decompose the vector into horizontal and vertical components. Suitable for students in Grades 9-12.

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