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The question asks for the horizontal component of **Vector A**. The information provided is:

- **Vector A** = 60 N, **245 degrees** from the +X-axis.

To find the horizontal component of a vector given its magnitude and direction, we use the following formula:

\[
A_x = A \cdot \cos(\theta)
\]

Where:
- \( A_x \) is the horizontal component of vector A.
- \( A \) is the magnitude of vector A (60 N).
- \( \theta \) is the angle of the vector measured counterclockwise from the +X-axis (245 degrees).

### Step-by-step calculation:
1. First, recognize that the angle of **245 degrees** places the vector in the third quadrant of the coordinate system, meaning the horizontal component will be negative.
2. Compute the horizontal component:

\[
A_x = 60 \cdot \cos(245^\circ)
\]

Let me calculate that for you.The horizontal component of **Vector A** is approximately \(-25.4\), rounded to 3 significant figures.

Would you like further clarification or details on any part of this process?

Here are 5 related questions for further practice:
1. What is the vertical component of Vector A?
2. How would you find the resultant vector of Vector A and Vector B?
3. What is the magnitude and direction of Vector C?
4. How do you add vectors using the analytical method?
5. How do you determine the quadrant a vector is in based on its angle?

**Tip**: Remember that when the angle is measured from the positive X-axis, the cosine gives the horizontal component, and sine gives the vertical component!

What is the horizontal component of Vector A? Vector A = 60 N, 245 degrees from +X-axis.

Learn how to find the horizontal component of Vector A (60 N) at 245 degrees from the +X-axis. This solution uses trigonometric functions to calculate the component based on the angle. Suitable for college-level physics students.

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