A 2,029 kg Ford Shelby F-150 is identified as traveling at 35 meters/second at a point in time and then 42 meters/second 2 seconds later.
 
What is the amount of Force added by the the acceleration over those 2 seconds?


To calculate the force applied due to acceleration over 2 seconds, we can use **Newton's Second Law of Motion**, which states:

\[
F = ma
\]

Where:
- \( F \) is the force,
- \( m \) is the mass of the object (in kilograms),
- \( a \) is the acceleration (in meters per second squared).

### Step 1: Calculate Acceleration

We can calculate acceleration \( a \) using the formula:

\[
a = \frac{{\Delta v}}{{\Delta t}}
\]

Where:
- \( \Delta v \) is the change in velocity,
- \( \Delta t \) is the change in time.

Given:
- Initial velocity \( v_1 = 35 \, \text{m/s} \),
- Final velocity \( v_2 = 42 \, \text{m/s} \),
- Time \( \Delta t = 2 \, \text{seconds} \).

Thus,

\[
a = \frac{v_2 - v_1}{\Delta t} = \frac{42 \, \text{m/s} - 35 \, \text{m/s}}{2 \, \text{s}} = \frac{7}{2} = 3.5 \, \text{m/s}^2
\]

### Step 2: Calculate the Force

Now we apply Newton's second law. The mass \( m \) of the Ford Shelby F-150 is 2,029 kg, and the acceleration \( a = 3.5 \, \text{m/s}^2 \). Therefore, the force \( F \) is:

\[
F = ma = 2029 \times 3.5 = 7101.5 \, \text{N}
\]

### Conclusion:
The force applied by the acceleration over the 2 seconds is **7,101.5 Newtons**.

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Would you like more details or have any questions about this? Here are five related questions:

1. How does Newton's second law apply to everyday vehicles?
2. What would the force be if the mass of the truck was different?
3. How would the calculation change if the time interval was shorter?
4. What effect does increasing acceleration have on the force?
5. How does force relate to momentum in this scenario?

**Tip:** To reduce acceleration impact on a vehicle, maintaining steady speeds and avoiding rapid changes can help reduce stress on the engine and improve fuel efficiency!

A 2,029 kg Ford Shelby F-150 is identified as traveling at 35 meters/second at a point in time and then 42 meters/second 2 seconds later. What is the amount of Force added by the acceleration over those 2 seconds?

Learn how to calculate the force applied to a 2,029 kg Ford Shelby F-150 accelerating from 35 m/s to 42 m/s over 2 seconds using Newton's Second Law of Motion. This problem involves key physics concepts such as acceleration and force, suitable for high school students in Grades 9-12.

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