A 2,206 kg Ford Shelby F-150 is identified as traveling at 37 meters/second at a point in time and then 44 meters/second 2 seconds later.

What is the amount of Force added by the the acceleration over those 2 seconds?

To calculate the force added by the acceleration over the 2 seconds, we can use **Newton's second law** of motion, which is:

\[
F = m \cdot a
\]

Where:
- \( F \) is the force,
- \( m \) is the mass of the object (in this case, 2,206 kg),
- \( a \) is the acceleration.

### Step 1: Calculate the Acceleration

Acceleration is defined as the change in velocity (\( \Delta v \)) divided by the time interval (\( \Delta t \)):

\[
a = \frac{\Delta v}{\Delta t}
\]

Here:
- Initial velocity (\( v_i \)) = 37 m/s,
- Final velocity (\( v_f \)) = 44 m/s,
- Time interval (\( \Delta t \)) = 2 seconds.

So the change in velocity (\( \Delta v \)) is:

\[
\Delta v = v_f - v_i = 44 \, \text{m/s} - 37 \, \text{m/s} = 7 \, \text{m/s}
\]

Now, calculate the acceleration:

\[
a = \frac{7 \, \text{m/s}}{2 \, \text{s}} = 3.5 \, \text{m/s}^2
\]

### Step 2: Calculate the Force

Now that we know the acceleration, we can calculate the force:

\[
F = m \cdot a = 2206 \, \text{kg} \cdot 3.5 \, \text{m/s}^2
\]

\[
F = 7,721 \, \text{N}
\]

Thus, the force added by the acceleration over the 2 seconds is **7,721 Newtons (N)**.

Would you like more details or have any questions about this calculation?

Here are five related questions:
1. How does Newton's second law apply to different types of forces?
2. What is the relationship between mass and acceleration in determining force?
3. How would a change in time affect the calculated force?
4. What would be the force if the vehicle's mass were doubled?
5. How can you convert the force into different units like pounds-force (lbf)?

**Tip:** When velocity increases or decreases, the change in momentum also plays a role in determining the net force applied.

A 2,206 kg Ford Shelby F-150 is identified as traveling at 37 meters/second at a point in time and then 44 meters/second 2 seconds later. What is the amount of Force added by the acceleration over those 2 seconds?

Discover how to calculate the force added by acceleration for a 2,206 kg Ford Shelby F-150 accelerating from 37 m/s to 44 m/s in 2 seconds. This solution uses Newton's Second Law of Motion and basic kinematics, suitable for students in Grades 9-12.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation