Math Problem Statement

1

Solution

To calculate the equivalent resistance in series and parallel circuits, we need to understand how resistors behave when connected in different configurations:

1. Resistors in Series:

  • When resistors are connected in series, the current through each resistor is the same, but the voltage across each resistor may differ.

  • The total or equivalent resistance ReqR_{\text{eq}} in a series circuit is the sum of the individual resistances: Req=R1+R2+R3++RnR_{\text{eq}} = R_1 + R_2 + R_3 + \dots + R_n

    Example:

    • If three resistors of 2Ω2 \, \Omega, 3Ω3 \, \Omega, and 4Ω4 \, \Omega are connected in series, the equivalent resistance is: Req=2Ω+3Ω+4Ω=9ΩR_{\text{eq}} = 2 \, \Omega + 3 \, \Omega + 4 \, \Omega = 9 \, \Omega

2. Resistors in Parallel:

  • When resistors are connected in parallel, the voltage across each resistor is the same, but the current through each resistor may differ.

  • The total or equivalent resistance ReqR_{\text{eq}} in a parallel circuit is given by the reciprocal of the sum of the reciprocals of the individual resistances: 1Req=1R1+1R2+1R3++1Rn\frac{1}{R_{\text{eq}}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3} + \dots + \frac{1}{R_n}

    • For two resistors: Req=R1×R2R1+R2R_{\text{eq}} = \frac{R_1 \times R_2}{R_1 + R_2}

    Example:

    • If three resistors of 2Ω2 \, \Omega, 3Ω3 \, \Omega, and 6Ω6 \, \Omega are connected in parallel, the equivalent resistance is: 1Req=12Ω+13Ω+16Ω=3+2+16Ω=66Ω=1Ω\frac{1}{R_{\text{eq}}} = \frac{1}{2 \, \Omega} + \frac{1}{3 \, \Omega} + \frac{1}{6 \, \Omega} = \frac{3 + 2 + 1}{6 \, \Omega} = \frac{6}{6 \, \Omega} = 1 \, \Omega Therefore, Req=1ΩR_{\text{eq}} = 1 \, \Omega.

Summary:

  • Series: Req=R1+R2+R3+R_{\text{eq}} = R_1 + R_2 + R_3 + \dots
  • Parallel: Req=(1Ri)1R_{\text{eq}} = \left(\sum \frac{1}{R_i}\right)^{-1}

Would you like to explore this further, or do you have any more specific questions? Here are some related questions:

  1. How do resistors affect the current in series vs. parallel circuits?
  2. What are some real-world applications of series and parallel resistor combinations?
  3. How does the concept of equivalent resistance apply to complex networks like Wheatstone bridges?
  4. What are the effects of adding more resistors in parallel on the total resistance?
  5. How can you determine the equivalent resistance of a mixed (series-parallel) resistor network?

Tip: Always simplify complex resistor networks step by step, combining resistors in series and parallel until you reach the simplest form.

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Math Problem Analysis

Mathematical Concepts

Electric Circuits
Series Circuits
Parallel Circuits
Equivalent Resistance

Formulas

Series Resistance: R_eq = R_1 + R_2 + R_3 + ...
Parallel Resistance: R_eq = (1 / R_1 + 1 / R_2 + 1 / R_3 + ...) ^ (-1)

Theorems

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Suitable Grade Level

High School