Math Problem Statement
Solution
To calculate the equivalent capacitance between points and , let's break down the circuit step by step:
Step 1: Combine capacitors in series or parallel
-
Left loop:
- The 6 µF and 1 µF capacitors are in series. For capacitors in series, the equivalent capacitance is given by: Substituting values: So:
-
Right loop:
- The 9 µF and 4 µF capacitors are also in series. Using the same formula: Compute as: So:
Step 2: Combine with middle capacitor
Now, the equivalent capacitances of the left loop () and right loop () are in parallel with the middle 1 µF capacitor. For capacitors in parallel, the equivalent capacitance is: Substitute the values:
Step 3: Compute final result
Simplify the terms:
- Convert and to a common denominator:
- Least common multiple of 7 and 13 is 91.
- , and .
- Add these along with :
Finally:
Final Answer:
The equivalent capacitance is approximately 4.63 µF.
Would you like additional clarification or details about any of the steps?
Relative Questions:
- How do capacitors combine in parallel versus series circuits?
- What are some common applications of capacitance in electrical circuits?
- How does the value of capacitance affect energy storage in a circuit?
- What happens if additional capacitors are added to this circuit in parallel?
- Can you explain the physical meaning of equivalent capacitance?
Tip:
Always double-check units when solving problems involving capacitance to ensure consistency across calculations.
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Math Problem Analysis
Mathematical Concepts
Capacitance
Series and Parallel Circuits
Formulas
1/Cs = 1/C1 + 1/C2 for capacitors in series
Cp = C1 + C2 + C3 for capacitors in parallel
Theorems
Capacitors in Series and Parallel Combination
Suitable Grade Level
Grades 10-12
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