Math Problem Statement

Calculate the equivalent capacitance Cab between points a and b. Answer in units of µF.

Solution

To calculate the equivalent capacitance CabC_{ab} between points aa and bb, let's break down the circuit step by step:

Step 1: Combine capacitors in series or parallel

  1. Left loop:

    • The 6 µF and 1 µF capacitors are in series. For capacitors in series, the equivalent capacitance CsC_s is given by: 1Cs=1C1+1C2\frac{1}{C_s} = \frac{1}{C_1} + \frac{1}{C_2} Substituting values: 1Cs=16+11=16+66=76\frac{1}{C_s} = \frac{1}{6} + \frac{1}{1} = \frac{1}{6} + \frac{6}{6} = \frac{7}{6} So: Cs=67μFC_s = \frac{6}{7} \, \mu\text{F}
  2. Right loop:

    • The 9 µF and 4 µF capacitors are also in series. Using the same formula: 1Cs=19+14\frac{1}{C_s} = \frac{1}{9} + \frac{1}{4} Compute 19+14\frac{1}{9} + \frac{1}{4} as: 1Cs=436+936=1336\frac{1}{C_s} = \frac{4}{36} + \frac{9}{36} = \frac{13}{36} So: Cs=3613μFC_s = \frac{36}{13} \, \mu\text{F}

Step 2: Combine with middle capacitor

Now, the equivalent capacitances of the left loop (67μF\frac{6}{7} \, \mu\text{F}) and right loop (3613μF\frac{36}{13} \, \mu\text{F}) are in parallel with the middle 1 µF capacitor. For capacitors in parallel, the equivalent capacitance is: Cp=C1+C2+C3C_p = C_1 + C_2 + C_3 Substitute the values: Cab=67+1+3613C_{ab} = \frac{6}{7} + 1 + \frac{36}{13}

Step 3: Compute final result

Simplify the terms:

  1. Convert 67\frac{6}{7} and 3613\frac{36}{13} to a common denominator:
    • Least common multiple of 7 and 13 is 91.
    • 67=7891\frac{6}{7} = \frac{78}{91}, and 3613=25291\frac{36}{13} = \frac{252}{91}.
  2. Add these along with 1=91911 = \frac{91}{91}: Cab=7891+9191+25291=42191μFC_{ab} = \frac{78}{91} + \frac{91}{91} + \frac{252}{91} = \frac{421}{91} \, \mu\text{F}

Finally: Cab4.63μFC_{ab} \approx 4.63 \, \mu\text{F}

Final Answer:

The equivalent capacitance CabC_{ab} is approximately 4.63 µF.


Would you like additional clarification or details about any of the steps?

Relative Questions:

  1. How do capacitors combine in parallel versus series circuits?
  2. What are some common applications of capacitance in electrical circuits?
  3. How does the value of capacitance affect energy storage in a circuit?
  4. What happens if additional capacitors are added to this circuit in parallel?
  5. Can you explain the physical meaning of equivalent capacitance?

Tip:

Always double-check units when solving problems involving capacitance to ensure consistency across calculations.

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Math Problem Analysis

Mathematical Concepts

Capacitance
Series and Parallel Circuits

Formulas

1/Cs = 1/C1 + 1/C2 for capacitors in series
Cp = C1 + C2 + C3 for capacitors in parallel

Theorems

Capacitors in Series and Parallel Combination

Suitable Grade Level

Grades 10-12