Given the problem of a car with an initial velocity 𝑣 𝑖

30   km/h v i ​ =30km/h, constant acceleration 𝑎

2   km/h 2 a=2km/h 2 , and time interval 𝑡 𝑖

20 t i ​ =20 seconds and 𝑡 𝑓

60 t f ​ =60 seconds, we can use the last formula shown on the blackboard:

𝑑

𝑣 𝑖 ( 𝑡 𝑓 − 𝑡 𝑖 ) + 1 2 𝑎 ( 𝑡 𝑓 − 𝑡 𝑖 ) 2 d=v i ​ (t f ​ −t i ​ )+ 2 1 ​ a(t f ​ −t i ​ ) 2

Step-by-Step Application: Convert time to hours:

𝑡 𝑖

20 3600 hours , 𝑡 𝑓

60 3600 hours t i ​

3600 20 ​ hours,t f ​

3600 60 ​ hours Substitute values:

𝑑

30 × ( 𝑡 𝑓 − 𝑡 𝑖 ) + 1 2 × 2 × ( 𝑡 𝑓 − 𝑡 𝑖 ) 2 d=30×(t f ​ −t i ​ )+ 2 1 ​ ×2×(t f ​ −t i ​ ) 2

Substitute 𝑡 𝑓 − 𝑡 𝑖

40 3600 hours

1 90 hours ≈ 0.0111 hours t f ​ −t i ​

3600 40 ​ hours= 90 1 ​ hours≈0.0111 hours. Compute:

𝑑 ≈ 30 × 0.0111 + 1 2 × 2 × ( 0.0111 ) 2 d≈30×0.0111+ 2 1 ​ ×2×(0.0111) 2

𝑑 ≈ 0.333 + 0.00012

0.33312   km d≈0.333+0.00012=0.33312km So, the distance traveled by the car during this time frame is approximately 0.33312 km.CaCan you turn the answer to 0.3334km