Math Problem Statement

What is the distance travelled by a car at a constant acceleration of 2 km/hr² when its initial velocity is 30km/hr during the time frame of Time initial = 20 seconds and Time final = 60 secnods

Solution

To find the distance traveled by the car during the specified time interval, we can use the equation for distance traveled under constant acceleration:

s=vit+12at2s = v_i t + \frac{1}{2} a t^2

However, since the time interval is given from t1=20t_1 = 20 seconds to t2=60t_2 = 60 seconds, we need to calculate the distance at both t1t_1 and t2t_2 and then subtract the two to find the distance traveled during this interval.

Given:

  • Initial velocity, vi=30v_i = 30 km/hr
  • Acceleration, a=2a = 2 km/hr²
  • t1=20t_1 = 20 seconds
  • t2=60t_2 = 60 seconds

Step 1: Convert the times to hours

Since the velocity and acceleration are given in km/hr and km/hr², respectively, we should convert the time from seconds to hours:

t1=203600 hours=1180 hourst_1 = \frac{20}{3600} \text{ hours} = \frac{1}{180} \text{ hours}

t2=603600 hours=160 hourst_2 = \frac{60}{3600} \text{ hours} = \frac{1}{60} \text{ hours}

Step 2: Calculate the distance at t2t_2

s2=vit2+12at22s_2 = v_i t_2 + \frac{1}{2} a t_2^2

s2=30×160+12×2×(160)2s_2 = 30 \times \frac{1}{60} + \frac{1}{2} \times 2 \times \left(\frac{1}{60}\right)^2

s2=0.5+11800 kms_2 = 0.5 + \frac{1}{1800} \text{ km}

s2=0.50056 kms_2 = 0.50056 \text{ km}

Step 3: Calculate the distance at t1t_1

s1=vit1+12at12s_1 = v_i t_1 + \frac{1}{2} a t_1^2

s1=30×1180+12×2×(1180)2s_1 = 30 \times \frac{1}{180} + \frac{1}{2} \times 2 \times \left(\frac{1}{180}\right)^2

s1=0.1667+164800 kms_1 = 0.1667 + \frac{1}{64800} \text{ km}

s1=0.1667 kms_1 = 0.1667 \text{ km}

Step 4: Calculate the distance traveled between t1t_1 and t2t_2

Δs=s2s1\Delta s = s_2 - s_1

Δs=0.500560.1667=0.33386 km\Delta s = 0.50056 - 0.1667 = 0.33386 \text{ km}

Answer:

The distance traveled by the car between 20 seconds and 60 seconds is approximately 0.334 km.

Would you like any further details or clarifications? Here are some related questions you might be interested in:

  1. How to find the final velocity of the car after 60 seconds?
  2. How does the distance traveled change if the acceleration was higher?
  3. What if the initial velocity was zero instead of 30 km/hr?
  4. How would the result differ if the acceleration was negative?
  5. How to calculate the time taken to travel a specific distance under constant acceleration?

Tip: Always ensure units are consistent when applying formulas in physics or mathematics.

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Math Problem Analysis

Mathematical Concepts

Kinematics
Constant acceleration

Formulas

Distance traveled under constant acceleration

Theorems

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Suitable Grade Level

Grades 11-12