A bus starting from rest moves with a uniform acceleration of 1m/s^2 for 2min find the distance traveled

To solve this problem, we can use the equations of motion for uniformly accelerated motion. The bus starts from rest, so the initial velocity (\( u \)) is 0. The acceleration (\( a \)) is given as \( 1 \, \text{m/s}^2 \), and the time (\( t \)) is 2 minutes.

First, convert the time from minutes to seconds:
\[
t = 2 \, \text{minutes} \times 60 \, \text{seconds/minute} = 120 \, \text{seconds}
\]

The equation to find the distance traveled (\( s \)) when starting from rest is:
\[
s = ut + \frac{1}{2}at^2
\]
Since \( u = 0 \), the equation simplifies to:
\[
s = \frac{1}{2}at^2
\]

Now plug in the values:
\[
s = \frac{1}{2} \times 1 \, \text{m/s}^2 \times (120 \, \text{seconds})^2
\]
\[
s = \frac{1}{2} \times 1 \times 14400 \, \text{m}
\]
\[
s = 7200 \, \text{meters}
\]

So, the distance traveled by the bus is **7200 meters**.

Would you like more details or have any other questions?

Here are five related questions:
1. How would the distance change if the acceleration was 2 m/s²?
2. What would be the final velocity of the bus after 2 minutes?
3. How long would it take the bus to travel 5000 meters with the same acceleration?
4. What if the bus had an initial velocity of 10 m/s? How would the distance traveled change?
5. How can you find the time required for the bus to reach a certain speed?

**Tip:** Always double-check unit conversions to ensure accuracy in your calculations.

Learn how to calculate the distance traveled by a bus starting from rest with a uniform acceleration of 1 m/s² over 2 minutes. Detailed step-by-step solution provided using the equations of motion. Suitable for high school students.

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