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To find the length of the interval \( PQ \), we can use the distance formula between two points in a coordinate plane. 

Given:
- \( P = (3, 1) \)
- \( Q = (7, 5) \)

The distance formula is:

\[
PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]

Substituting in the coordinates of points \( P \) and \( Q \):

\[
PQ = \sqrt{(7 - 3)^2 + (5 - 1)^2}
\]

Calculating each part:

1. \( (7 - 3)^2 = 4^2 = 16 \)
2. \( (5 - 1)^2 = 4^2 = 16 \)

Adding these:

\[
PQ = \sqrt{16 + 16} = \sqrt{32}
\]

Now, simplifying \(\sqrt{32}\):

\[
PQ = \sqrt{32} \approx 5.7
\]

Thus, the length of \( PQ \) to one decimal place is approximately:

\[
PQ = 5.7
\]

Would you like further details or have any questions on this? Here are some additional questions related to this topic:

1. How can you apply the distance formula to find the distance between two points in 3D space?
2. What are some practical applications of the distance formula in geometry or physics?
3. How does the Pythagorean theorem relate to the distance formula?
4. Can you calculate the midpoint of the line segment \( PQ \) given its coordinates?
5. How would the calculation change if the points \( P \) and \( Q \) were rotated around the origin?

**Tip:** When using the distance formula, always double-check the subtraction of coordinates and squaring to avoid sign errors.

Learn how to calculate the distance between two points on a coordinate plane using the distance formula. This example finds the length of interval PQ, with points P(3, 1) and Q(7, 5), resulting in a distance of approximately 5.7 units. Ideal for Grades 7-9 students studying coordinate geometry.

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