Math Problem Statement

What is the length of segment PQ in units?

Solution

To determine the length of the segment PQPQ, we use the distance formula:

d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Here:

  • Point PP has coordinates (6,12)(6, 12)
  • Point QQ has coordinates (10,5)(10, 5)

Substitute these values into the formula:

d=(106)2+(512)2d = \sqrt{(10 - 6)^2 + (5 - 12)^2}

Simplify:

d=(4)2+(7)2d = \sqrt{(4)^2 + (-7)^2} d=16+49d = \sqrt{16 + 49} d=65d = \sqrt{65}

The length of segment PQPQ is approximately:

658.06 units\sqrt{65} \approx 8.06 \text{ units}

Let me know if you'd like more details or clarifications.


Related Questions:

  1. How can we find the distance between any two points in 3D space?
  2. What is the geometric interpretation of the distance formula?
  3. Can you explain how the Pythagorean Theorem is applied in this formula?
  4. How would the length of PQPQ change if PP or QQ were moved?
  5. How can this be used to find the perimeter of a polygon?

Tip:

Always double-check coordinates before substituting into formulas to avoid calculation errors!

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Math Problem Analysis

Mathematical Concepts

Geometry
Distance Formula
Coordinate Geometry

Formulas

Distance Formula: d = √((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 6-8