Math Problem Statement

What is the distance between the two points on the coordinate plane shown?

Solution

It looks like you are working on a geometry question about finding the distance between two points on a coordinate plane. Based on the image, we have two points on the grid.

We can apply the distance formula to find the distance between the two points: d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} The two points on the graph are approximately at:

  • Point 1: (3,5)(3, 5)
  • Point 2: (7,5)(7, -5)

Now, using the distance formula:

  1. x1=3x_1 = 3, y1=5y_1 = 5
  2. x2=7x_2 = 7, y2=5y_2 = -5

Substitute these into the formula:

d=(73)2+(55)2d = \sqrt{(7 - 3)^2 + (-5 - 5)^2} d=(4)2+(10)2d = \sqrt{(4)^2 + (-10)^2} d=16+100d = \sqrt{16 + 100} d=116d = \sqrt{116} This simplifies to approximately 116\sqrt{116}, which is not a perfect square, but its approximate value is around 10.7710.77.

From the options, the closest answer is 97\sqrt{97}, so that's the answer to select.

Do you have any questions, or would you like further details?


Here are 5 related questions you could explore:

  1. What is the distance between two points with coordinates (2,3)(2, 3) and (5,7)(5, 7)?
  2. How does the midpoint formula relate to the distance formula?
  3. What happens if the points lie on the same vertical or horizontal line?
  4. How can the distance formula be derived from the Pythagorean theorem?
  5. How do you find the distance in three-dimensional space?

Tip: The distance formula is just an application of the Pythagorean theorem, so whenever you're unsure, think of the right triangle formed by the points.

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Math Problem Analysis

Mathematical Concepts

Analytic Geometry
Coordinate Plane
Distance Formula

Formulas

d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 9-10