Math Problem Statement

Work out this math questions

Find the length of the interval PQ.

Solution

To find the length of the interval PQPQ between points PP and QQ on a coordinate plane, we can use the distance formula:

PQ=(x2x1)2+(y2y1)2PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

From the graph:

  • Point PP has coordinates (3,1)(3, 1).
  • Point QQ has coordinates (7,5)(7, 5).

Now we can plug these coordinates into the formula:

PQ=(73)2+(51)2PQ = \sqrt{(7 - 3)^2 + (5 - 1)^2} =42+42= \sqrt{4^2 + 4^2} =16+16= \sqrt{16 + 16} =32= \sqrt{32} =16×2=425.7= \sqrt{16 \times 2} = 4\sqrt{2} \approx 5.7

So, the length of PQPQ is approximately 5.75.7 (to 1 decimal place).

Would you like more details on this solution, or do you have any questions?


Here are five related questions to expand your understanding:

  1. How do we derive the distance formula from the Pythagorean theorem?
  2. What are some other applications of the distance formula in real-world scenarios?
  3. How would the distance change if point QQ moved horizontally or vertically?
  4. What would happen if the coordinates of PP or QQ were negative values?
  5. Can you determine the midpoint of PQPQ using its coordinates?

Tip: Always check the coordinates carefully before substituting values into the distance formula to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Distance Between Two Points

Formulas

Distance formula: d = √((x2 - x1)^2 + (y2 - y1)^2)

Theorems

Pythagorean theorem

Suitable Grade Level

Grades 8-10