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To find the displacement of the car as it skids to a stop, we can use the kinematic equation:

\[ s = vt + \frac{1}{2}at^2 \]

where:
- \( s \) is the displacement
- \( v \) is the initial velocity
- \( a \) is the acceleration
- \( t \) is the time

Since the car comes to a stop, the final velocity \( v_f \) is 0 m/s. We can first find the acceleration using the formula:

\[ v_f = v + at \]

Substituting the values:

\[ 0 = 42 + a \times 4 \]

\[ a = -\frac{42}{4} = -10.5 \, \text{m/s}^2 \]

Now, substitute \( a \) and \( v \) into the displacement formula:

\[ s = 42 \times 4 + \frac{1}{2}(-10.5) \times (4^2) \]

\[ s = 168 - 84 = 84 \, \text{m} \]

Thus, the displacement of the car as it skids to a stop is 84 meters. This is rounded to two significant digits as \( 84 \, \text{m} \).

Would you like more details or have any other questions? Here are some follow-up topics:
1. What would the displacement be if the time taken to stop was different?
2. How would the displacement change if the initial speed was higher or lower?
3. Can we find the distance using another kinematic equation?
4. What factors can affect the deceleration rate of a vehicle?
5. How does the constant acceleration assumption affect our calculations?

**Tip:** In kinematic problems like this, drawing a velocity-time graph can help visualize changes in speed and calculate areas under the graph to find displacement.

A car is traveling to the right with a speed of 42 m/s when the driver applies the brakes. It takes the car 4.0 s to come to a stop with constant acceleration. What is the displacement of the car as it skids to a stop?

Find the displacement of a car traveling at 42 m/s that comes to a stop in 4.0 seconds with constant acceleration. Learn about kinematic equations and how to apply them to real-world problems. Suitable for high school students in Grades 10-12.

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