Math Problem Statement

A can complete the work in 18 days and A and B together can complete the half of the work in 6 days. C is 20% more efficient than B. In how many days A,B and C together can complete the 84% of the work?

Solution

Let's break the problem into manageable parts and solve it step-by-step.

Step 1: A's work rate

A can complete the work in 18 days. Therefore, A's work rate is:

A’s rate=118 work per day.\text{A's rate} = \frac{1}{18} \text{ work per day}.

Step 2: A and B's combined rate

A and B together can complete half of the work in 6 days. So, A and B together can complete 12\frac{1}{2} of the work in 6 days. Their combined work rate is:

(A + B)’s rate=1/26=112 work per day.\text{(A + B)'s rate} = \frac{1/2}{6} = \frac{1}{12} \text{ work per day}.

We already know A's rate is 118\frac{1}{18}. To find B's rate, we subtract A's rate from the combined rate:

B’s rate=112118.\text{B's rate} = \frac{1}{12} - \frac{1}{18}.

To subtract, find a common denominator:

B’s rate=336236=136 work per day.\text{B's rate} = \frac{3}{36} - \frac{2}{36} = \frac{1}{36} \text{ work per day}.

Step 3: C's rate

C is 20% more efficient than B, meaning C's work rate is 120% of B's rate:

C’s rate=1.2×B’s rate=1.2×136=1.236=130 work per day.\text{C's rate} = 1.2 \times \text{B's rate} = 1.2 \times \frac{1}{36} = \frac{1.2}{36} = \frac{1}{30} \text{ work per day}.

Step 4: Combined rate of A, B, and C

Now, let's find the combined rate of A, B, and C:

(A + B + C)’s rate=A’s rate+B’s rate+C’s rate.\text{(A + B + C)'s rate} = \text{A's rate} + \text{B's rate} + \text{C's rate}. Substitute the values:

(A + B + C)’s rate=118+136+130.\text{(A + B + C)'s rate} = \frac{1}{18} + \frac{1}{36} + \frac{1}{30}.

To add these, find the common denominator, which is 180:

118=10180,136=5180,130=6180.\frac{1}{18} = \frac{10}{180}, \quad \frac{1}{36} = \frac{5}{180}, \quad \frac{1}{30} = \frac{6}{180}.

Now, add the fractions:

(A + B + C)’s rate=10180+5180+6180=21180=760 work per day.\text{(A + B + C)'s rate} = \frac{10}{180} + \frac{5}{180} + \frac{6}{180} = \frac{21}{180} = \frac{7}{60} \text{ work per day}.

Step 5: Time to complete 84% of the work

A, B, and C together complete 760\frac{7}{60} of the work in 1 day. To find how many days it takes them to complete 84% (or 0.840.84) of the work, we use the formula:

Time=0.84(A + B + C)’s rate=0.84760=0.84×607=50.47=7.2 days.\text{Time} = \frac{0.84}{\text{(A + B + C)'s rate}} = \frac{0.84}{\frac{7}{60}} = 0.84 \times \frac{60}{7} = \frac{50.4}{7} = 7.2 \text{ days}.

Final Answer:

It will take A, B, and C together 7.2 days to complete 84% of the work.

Would you like more details or have any questions? Here are 5 related questions:

  1. How would the total work time change if C were 30% more efficient than B?
  2. How long would it take for only B and C to complete the entire work together?
  3. If A worked alone, how long would it take to complete 75% of the work?
  4. What if A, B, and C worked together for 5 days—how much work would be completed?
  5. How much time would B need alone to finish 50% of the work?

Tip: When working with rates, always remember that time and efficiency are inversely related. More efficiency means less time needed to complete the same work.

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Math Problem Analysis

Mathematical Concepts

Work and Time
Rates of Work
Percentage Efficiency

Formulas

Work Rate = 1 / Time
Combined Work Rate = Rate_A + Rate_B + Rate_C
C's Rate = 1.2 * B's Rate
Time = Work Fraction / Combined Rate

Theorems

Inversely Proportional Relationship between Time and Rate

Suitable Grade Level

Grades 9-12