To solve this problem, we need to determine the axial force component $F_a$ of the given force $F = 1500 \, \text{N}$ in the specified direction. Given that the angle $\theta = 60^\circ$, the axial force $F_a$ can be found using trigonometric principles, specifically the cosine component along the axis of interest.

Calculation:

The axial force $F_a$ is given by: $F_a = F \cdot \cos(\theta)$

Substituting the values:

• $F = 1500 \, \text{N}$
• $\theta = 60^\circ$

$F_a = 1500 \, \text{N} \cdot \cos(60^\circ)$

Since $\cos(60^\circ) = 0.5$: $F_a = 1500 \, \text{N} \cdot 0.5 = 750 \, \text{N}$

Answer:

The axial force $F_a$ is $750 \, \text{N}$.

Would you like further details or have any questions?

Here are five related questions you might explore:

1. How would you calculate the perpendicular (shear) force component for this force?
2. What if the angle were different—how would the axial force change?
3. How do you calculate the resultant force if multiple forces are acting at various angles?
4. What would be the effect of changing the force $F$ while keeping the angle constant?
5. Can you explain the significance of the axial force in structural applications?

Tip: When resolving forces, always identify the angle with respect to the desired axis to use the correct trigonometric function (sine or cosine).