To solve this problem, we need to break down the forces $P = 200 \, \text{N}$ and $F = 300 \, \text{N}$ into their components along the X and Y axes.

Force $P$ (200 N at 60° from the horizontal)

For $P = 200 \, \text{N}$ at an angle of $60^\circ$:

• $P_x = P \cdot \cos(60^\circ) = 200 \cdot 0.5 = 100 \, \text{N}$
• $P_y = P \cdot \sin(60^\circ) = 200 \cdot \frac{\sqrt{3}}{2} \approx 173.2 \, \text{N}$

Thus, the components for $P$ are:

• $P_x = 100 \, \text{N}$
• $P_y = 173.2 \, \text{N}$

Force $F$ (300 N at 30° from the horizontal)

For $F = 300 \, \text{N}$ at an angle of $30^\circ$ from the horizontal:

• $F_x = F \cdot \cos(30^\circ) = 300 \cdot \frac{\sqrt{3}}{2} \approx 259.8 \, \text{N}$
• $F_y = F \cdot \sin(30^\circ) = 300 \cdot 0.5 = 150 \, \text{N}$

After comparing these calculations with the options, none of the options exactly match these computed values, indicating a potential discrepancy in provided answers or in problem details.

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