Math Problem Statement

A group walked along a bearing of 50 from point A to B for 10km. they then walked on a bearing of 210 to point C and then back to A on a bearing of 310. what is the area of the triangle. find the area

Solution

To solve this problem, we need to find the area of the triangle formed by the points AA, BB, and CC using the given bearings and distances. Let's break down the problem step by step:

Step 1: Convert Bearings to Angles

Bearings are measured clockwise from the north. We need to determine the internal angles of the triangle.

  1. Bearing from AA to BB: 5050^\circ
  2. Bearing from BB to CC: 210210^\circ
  3. Bearing from CC back to AA: 310310^\circ

We need to find the angles ABC\angle ABC, BCA\angle BCA, and CAB\angle CAB.

  • The internal angle at BB is the difference between the bearing of BB to CC and AA to BB: ABC=21050=160\angle ABC = 210^\circ - 50^\circ = 160^\circ

  • The internal angle at CC is the difference between the bearing of CC to AA and BB to CC: BCA=310210=100\angle BCA = 310^\circ - 210^\circ = 100^\circ

  • The internal angle at AA can be calculated as: CAB=360(ABC+BCA)=360(160+100)=100\angle CAB = 360^\circ - (\angle ABC + \angle BCA) = 360^\circ - (160^\circ + 100^\circ) = 100^\circ

Step 2: Use the Law of Cosines

We need to find the lengths of all sides. We know the side AB=10AB = 10 km.

Assume BC=xBC = x and AC=yAC = y.

We can use the Law of Cosines in triangle ABCABC:

  1. For side BCBC: x2=AB2+AC22(AB)(AC)cos(BAC)x^2 = AB^2 + AC^2 - 2(AB)(AC)\cos(\angle BAC)

  2. For side ACAC: y2=AB2+BC22(AB)(BC)cos(ABC)y^2 = AB^2 + BC^2 - 2(AB)(BC)\cos(\angle ABC)

However, since we only need the area, we can use the Sine Rule for Area. The area Area\text{Area} of the triangle can be found by: Area=12×AB×BC×sin(ABC)\text{Area} = \frac{1}{2} \times AB \times BC \times \sin(\angle ABC) But this formula needs both sides and the included angle. Instead, let’s use the cosine method:

Area=12×AB×AC×sin(CAB)\text{Area} = \frac{1}{2} \times AB \times AC \times \sin(\angle CAB)

Since this seems more complex than necessary, let’s simplify and proceed using trigonometry:

The distance calculation or the simplified formula needed will be complex so let's skip to solving for an explicit triangle area. With the 3 angles, we can use Heron's formula. Using:

A=12×AB×AC×sin(ABC)A = \frac{1}{2} \times AB \times AC \times \sin(\angle ABC)

But exact side lengths needed to complete it are more suited to exact side calculations rather than 3 internal angles simplification.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Geometry

Formulas

Law of Cosines
Sine Rule for Area
Heron's Formula

Theorems

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Suitable Grade Level

Grades 10-12