Math Problem Statement

Solve

Calculate the area of the triangle given side length and angles in the image.

Solution

The task consists of two parts based on the instructions and the triangle diagram provided in the image.

  1. Calculate the area of the triangle.

    Given dataThe task consists of two parts based on the instructions and the triangle diagram provided in the image.

  2. Calculate the area of the triangle.

    Given

    • Side length AB=157mAB = 157 \, \text{m}
    • Angle at point BB is 6161^\circ
    • Angle at point AA is 4444^\circ

    To find the area of the triangle, we can use the formula: Area=12absin(C)\text{Area} = \frac{1}{2} a b \sin(C) where CC is the angle between sides aa and bb.

    Since we only know one side length (157 m) and two angles, we need to use the Law of Sines to find the other sides.

    Let's proceed with the calculations.

Step-by-Step Solution

  1. Find the third angle CC of the triangle (opposite to side ABAB): C=1804461=75C = 180^\circ - 44^\circ - 61^\circ = 75^\circ

  2. Using the Law of Sines to find the other sides: asinA=bsinB=csinC\frac{a}{\sin A} = \frac{b}{\sin B} = \frac{c}{\sin C} Let AB=c=157mAB = c = 157 \, \text{m}, and use: 157sin75=asin44=bsin61\frac{157}{\sin 75^\circ} = \frac{a}{\sin 44^\circ} = \frac{b}{\sin 61^\circ}

    • Solving for aa: a=157×sin44sin75a = 157 \times \frac{\sin 44^\circ}{\sin 75^\circ}

    • Solving for bb: b=157×sin61sin75b = 157 \times \frac{\sin 61^\circ}{\sin 75^\circ}

  3. Calculate the area using Area=12absin(C)\text{Area} = \frac{1}{2} a b \sin(C) once aa and bb are known.

I’ll continue with these calculations.The calculations yield the following results:

  1. Side aa (opposite the 6161^\circ angle) is approximately 112.91m112.91 \, \text{m}.
  2. Side bb (opposite the 4444^\circ angle) is approximately 142.16m142.16 \, \text{m}.
  3. The area of the triangle is approximately 7752.04m27752.04 \, \text{m}^2.

Would you like more details on any part of this solution?

Here are five related questions to explore further:

  1. How would you solve for other missing measurements if only one angle and two sides were known?
  2. How can the Law of Cosines be used instead of the Law of Sines for similar problems?
  3. What if the angle opposite the known side was obtuse? How would that affect calculations?
  4. How can we calculate the perimeter of the triangle using these side lengths?
  5. What other methods can we use to find the area of a triangle when given different information?

Tip: When solving for triangle sides or angles, always ensure your calculator is in the correct mode (degrees or radians) to avoid errors in trigonometric calculations.

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Math Problem Analysis

Mathematical Concepts

Geometry
Trigonometry
Triangle Area Calculation
Law of Sines

Formulas

Area = 0.5 * a * b * sin(C)
Law of Sines: a/sin(A) = b/sin(B) = c/sin(C)

Theorems

Law of Sines

Suitable Grade Level

Grades 10-12