Math Problem Statement

A disk starting from rest takes 10 revolutions to reach an angular velocity ω at constant angular acceleration. How many additional revolutions are required to reach an angular velocity of √2 ω?

Solution

To solve this problem, let's go through the steps systematically.

  1. Given Information:

    • The disk starts from rest, so the initial angular velocity ω0=0\omega_0 = 0.
    • It takes 10 revolutions to reach an angular velocity ω\omega at constant angular acceleration α\alpha.
  2. Relevant Equations: For an object under constant angular acceleration, the relationship between angular displacement θ\theta, initial angular velocity ω0\omega_0, final angular velocity ω\omega, and angular acceleration α\alpha is given by: ω2=ω02+2αθ\omega^2 = \omega_0^2 + 2 \alpha \theta

  3. Step 1: Determine α\alpha in Terms of ω\omega:

    • Convert 10 revolutions into radians. Since one revolution is 2π2 \pi radians, 10 revolutions is: θ=10×2π=20π radians\theta = 10 \times 2\pi = 20\pi \text{ radians}
    • Using the equation ω2=ω02+2αθ\omega^2 = \omega_0^2 + 2 \alpha \theta: ω2=0+2α(20π)\omega^2 = 0 + 2 \alpha (20\pi) α=ω240π\alpha = \frac{\omega^2}{40\pi}
  4. Step 2: Determine the Angular Displacement to Reach 2ω\sqrt{2} \omega:

    • The new angular velocity is 2ω\sqrt{2} \omega.
    • Using the same formula: (2ω)2=0+2αθnew(\sqrt{2} \omega)^2 = 0 + 2 \alpha \theta_{\text{new}}
    • Expanding (2ω)2(\sqrt{2} \omega)^2: 2ω2=2αθnew2 \omega^2 = 2 \alpha \theta_{\text{new}}
    • Substitute α=ω240π\alpha = \frac{\omega^2}{40\pi} from earlier: 2ω2=2(ω240π)θnew2 \omega^2 = 2 \left( \frac{\omega^2}{40\pi} \right) \theta_{\text{new}} θnew=40π\theta_{\text{new}} = 40 \pi
  5. Step 3: Calculate Additional Revolutions:

    • The total displacement to reach 2ω\sqrt{2} \omega is 40π40 \pi radians.
    • The additional revolutions required are: θadditional=θnewθ=40π20π=20π radians\theta_{\text{additional}} = \theta_{\text{new}} - \theta = 40 \pi - 20 \pi = 20 \pi \text{ radians}
    • Converting 20π20 \pi radians back to revolutions: Additional revolutions=20π2π=10\text{Additional revolutions} = \frac{20 \pi}{2 \pi} = 10

Answer: The disk requires an additional 10 revolutions to reach an angular velocity of 2ω\sqrt{2} \omega.

Would you like further details on any step, or have additional questions?


Follow-up Questions:

  1. What is the relationship between angular acceleration and angular velocity?
  2. How would the solution change if the initial angular velocity were not zero?
  3. What would happen to the number of additional revolutions if the angular acceleration were doubled?
  4. How can this concept apply to rotational motion in mechanical systems?
  5. What are the physical units associated with each variable in this problem?

Tip: Always convert units consistently when dealing with angular quantities in rotational motion problems.

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Math Problem Analysis

Mathematical Concepts

Rotational Motion
Angular Velocity
Angular Acceleration
Kinematics

Formulas

ω² = ω₀² + 2αθ
θ = ω² / (2α)

Theorems

Kinematic Equations for Rotational Motion

Suitable Grade Level

Grades 11-12