Math Problem Statement

A disk starting from rest takes 10 revolutions to reach an angular velocity ω at constant angular acceleration. How many additional revolutions are required to reach an angular velocity of √2 ω?

Solution

To solve this problem, we can use the equations of rotational motion with constant angular acceleration. Here’s the approach step-by-step.

Given:

  • Initial angular velocity (ω0\omega_0) = 0 (since the disk starts from rest)
  • Let n1=10n_1 = 10 revolutions required to reach angular velocity ω\omega.
  • Final angular velocity in the first phase (ω\omega) is reached after 10 revolutions.
  • We need to find the additional revolutions n2n_2 required to reach an angular velocity of 2ω\sqrt{2} \omega.

Step 1: Relate Revolutions to Angular Velocity

For rotational motion, we can use the following kinematic equation: ω2=ω02+2αθ\omega^2 = \omega_0^2 + 2 \alpha \theta where:

  • ω\omega is the final angular velocity,
  • ω0\omega_0 is the initial angular velocity,
  • α\alpha is the angular acceleration, and
  • θ\theta is the angular displacement in radians.

Since ω0=0\omega_0 = 0, this simplifies to: ω2=2αθ\omega^2 = 2 \alpha \theta

Step 2: Find α\alpha in Terms of ω\omega

For the first 10 revolutions, we have: ω2=2α(10×2π)=20απ\omega^2 = 2 \alpha (10 \times 2\pi) = 20 \alpha \pi So, α=ω220π\alpha = \frac{\omega^2}{20 \pi}

Step 3: Calculate Revolutions for 2ω\sqrt{2} \omega

Now we need the total revolutions to reach 2ω\sqrt{2} \omega as the final angular velocity. Using the same kinematic equation: (2ω)2=2αθ(\sqrt{2} \omega)^2 = 2 \alpha \theta 2ω2=2αθ2 \omega^2 = 2 \alpha \theta

Substitute α=ω220π\alpha = \frac{\omega^2}{20 \pi}: 2ω2=2(ω220π)θ2 \omega^2 = 2 \left(\frac{\omega^2}{20 \pi}\right) \theta θ=20π revolutions\theta = 20 \pi \text{ revolutions}

Step 4: Find Additional Revolutions

The additional revolutions n2n_2 required are: n2=θ10=2010=10 revolutionsn_2 = \theta - 10 = 20 - 10 = 10 \text{ revolutions}

Thus, 10 additional revolutions are required.

Would you like further clarification on any part of this solution?

Related Questions:

  1. What if the disk took 15 revolutions to reach angular velocity ω\omega instead?
  2. How does this calculation change if the angular acceleration is not constant?
  3. How many total revolutions would be needed to reach 2ω2 \omega instead of 2ω\sqrt{2} \omega?
  4. Can this approach be used for linear motion problems as well? How?
  5. How does the angular displacement affect the time taken if the initial velocity is not zero?

Tip:

Always remember to convert revolutions to radians when dealing with rotational kinematic equations, as radians are the standard unit for angular displacement in physics.

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Math Problem Analysis

Mathematical Concepts

Rotational Kinematics
Angular Velocity
Constant Angular Acceleration

Formulas

ω² = ω₀² + 2αθ
θ = (ω²)/(2α)

Theorems

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Suitable Grade Level

College Level Physics