A car at a stop light increases its speed to 
25
25 m/s down a straight road in 
9
9 seconds.

What is the acceleration of the car?

To find the acceleration of the car, we can use the following formula from kinematics:

\[
a = \frac{{\Delta v}}{{\Delta t}}
\]

Where:
- \( a \) is the acceleration,
- \( \Delta v \) is the change in velocity,
- \( \Delta t \) is the time over which the change occurs.

In this case:
- The final velocity (\( v_f \)) is \( 25 \, \text{m/s} \),
- The initial velocity (\( v_i \)) is \( 0 \, \text{m/s} \) (since the car starts from rest),
- The time (\( \Delta t \)) is \( 9 \, \text{seconds} \).

Now, we plug in the values:

\[
a = \frac{{25 - 0}}{{9}} = \frac{25}{9} \approx 2.78 \, \text{m/s}^2
\]

So, the acceleration of the car is approximately **2.78 m/s²**.

Would you like a more detailed explanation or have any questions?

Here are 5 related questions to think about:
1. What would be the car's displacement after 9 seconds?
2. How would the acceleration change if the car reached 50 m/s in 9 seconds instead?
3. What is the significance of constant acceleration in this scenario?
4. How long would it take for the car to reach 50 m/s with the same acceleration?
5. What is the total distance the car would travel if it continued accelerating at this rate for 20 seconds?

**Tip:** Acceleration is the rate of change of velocity, and constant acceleration means velocity increases at a steady rate.

A car at a stop light increases its speed to 25 m/s down a straight road in 9 seconds. What is the acceleration of the car?

Learn how to calculate the acceleration of a car that increases its speed to 25 m/s in 9 seconds using the formula a = Δv / Δt. This problem covers key physics concepts, including linear motion and acceleration. Suitable for students in Grades 9-12.

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