To find the acceleration of the car, we can use the following formula from kinematics:

$a = \frac{{\Delta v}}{{\Delta t}}$

Where:

• $a$ is the acceleration,
• $\Delta v$ is the change in velocity,
• $\Delta t$ is the time over which the change occurs.

In this case:

• The final velocity ($v_f$) is $25 \, \text{m/s}$,
• The initial velocity ($v_i$) is $0 \, \text{m/s}$ (since the car starts from rest),
• The time ($\Delta t$) is $9 \, \text{seconds}$.

Now, we plug in the values:

$a = \frac{{25 - 0}}{{9}} = \frac{25}{9} \approx 2.78 \, \text{m/s}^2$

So, the acceleration of the car is approximately 2.78 m/s².

Would you like a more detailed explanation or have any questions?

Here are 5 related questions to think about:

1. What would be the car's displacement after 9 seconds?
2. How would the acceleration change if the car reached 50 m/s in 9 seconds instead?
3. What is the significance of constant acceleration in this scenario?
4. How long would it take for the car to reach 50 m/s with the same acceleration?
5. What is the total distance the car would travel if it continued accelerating at this rate for 20 seconds?

Tip: Acceleration is the rate of change of velocity, and constant acceleration means velocity increases at a steady rate.