https://file.aiquickdraw.com/mathbot/file/1726049811376xx3cw7jt.jpg

The question asks us to find the acceleration of the object from the given speed-time graph. 

### Understanding the Graph:
- The graph shows the object's speed increasing linearly from 25 m/s to 80 m/s over a period of 30 seconds.
- This is a classic case of constant acceleration, as the speed is increasing uniformly.

### To Calculate the Acceleration:
Acceleration (\(a\)) is given by the formula:
\[
a = \frac{\Delta v}{\Delta t}
\]
Where:
- \(\Delta v\) is the change in speed (final speed - initial speed).
- \(\Delta t\) is the change in time.

From the graph:
- Initial speed (\(v_i\)) = 25 m/s
- Final speed (\(v_f\)) = 80 m/s
- Time interval (\(t\)) = 30 s

Now, let's calculate:

\[
\Delta v = v_f - v_i = 80 - 25 = 55 \, \text{m/s}
\]
\[
a = \frac{55}{30} = 1.83 \, \text{m/s}^2
\]

Thus, the acceleration of the object is **1.83 m/s²**.

Let me know if you need more details, or if you have any questions!

### Related Questions:
1. What is the formula for acceleration in terms of velocity and time?
2. How does a constant acceleration appear on a speed-time graph?
3. What is the significance of the slope in a speed-time graph?
4. How would the graph look for a decelerating object?
5. What is the difference between speed and velocity?

**Tip:** In speed-time graphs, the slope of the line gives the acceleration—positive for speeding up and negative for slowing down.

The diagram shows the speed-time graph of an object. Find the acceleration of the object in m/s².

Learn how to calculate the acceleration of an object based on its speed-time graph. This problem involves using the formula for acceleration (a = Δv / Δt) where the speed changes from 25 m/s to 80 m/s over a period of 30 seconds. Suitable for students in Grades 9-11.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation