The question asks us to find the acceleration of the object from the given speed-time graph.

Understanding the Graph:

• The graph shows the object's speed increasing linearly from 25 m/s to 80 m/s over a period of 30 seconds.
• This is a classic case of constant acceleration, as the speed is increasing uniformly.

To Calculate the Acceleration:

Acceleration ($a$) is given by the formula: $a = \frac{\Delta v}{\Delta t}$ Where:

• $\Delta v$ is the change in speed (final speed - initial speed).
• $\Delta t$ is the change in time.

From the graph:

• Initial speed ($v_i$) = 25 m/s
• Final speed ($v_f$) = 80 m/s
• Time interval ($t$) = 30 s

Now, let's calculate:

$\Delta v = v_f - v_i = 80 - 25 = 55 \, \text{m/s}$ $a = \frac{55}{30} = 1.83 \, \text{m/s}^2$

Thus, the acceleration of the object is 1.83 m/s².

Let me know if you need more details, or if you have any questions!

Related Questions:

1. What is the formula for acceleration in terms of velocity and time?
2. How does a constant acceleration appear on a speed-time graph?
3. What is the significance of the slope in a speed-time graph?
4. How would the graph look for a decelerating object?
5. What is the difference between speed and velocity?

Tip: In speed-time graphs, the slope of the line gives the acceleration—positive for speeding up and negative for slowing down.