To solve for the acceleration of the car, we can use the formula:

$a = \frac{\Delta V}{t}$

Where:

• $\Delta V$ is the change in velocity,
• $t$ is the time over which this change occurs.

Given:

• Initial velocity $V_i = 20 \, \text{m/s}$,
• Final velocity $V_f = 34 \, \text{m/s}$,
• Time $t = 10 \, \text{s}$.

First, we find $\Delta V$: $\Delta V = V_f - V_i = 34 \, \text{m/s} - 20 \, \text{m/s} = 14 \, \text{m/s}.$

Now we calculate the acceleration: $a = \frac{14 \, \text{m/s}}{10 \, \text{s}} = 1.4 \, \text{m/s}^2.$

So, the acceleration of the car is $1.4 \, \text{m/s}^2$.