We are given the function $F(P, Q, R, S)$ as the product of minterms $\pi(3, 5, 7, 8, 10, 11, 12, 13)$, which is a Product of Maxterms (POS) expression. To minimize it, we need to convert it into its corresponding Sum of Minterms (SOP) form and simplify it.

Steps to minimize:

1. Find the minterms complement to the given maxterms: The function $F(P, Q, R, S)$ can be represented by the missing minterms (i.e., those not listed in the maxterm form). These missing minterms are:

   $\text{Minterms} = \{0, 1, 2, 4, 6, 9, 14, 15\}$

2. Construct the Boolean function in SOP form: These minterms correspond to the binary representations of the values 0, 1, 2, 4, 6, 9, 14, and 15, with each minterm corresponding to the variables $P, Q, R, S$ as follows:

   Minterm	$P$	$Q$	$R$	$S$
   0	0	0	0	0
   1	0	0	0	1
   2	0	0	1	0
   4	0	1	0	0
   6	0	1	1	0
   9	1	0	0	1
   14	1	1	1	0
   15	1	1	1	1

3. Apply Karnaugh Map (K-map) simplification: We can now plot these minterms on a 4-variable K-map to find the simplest expression.

4. Simplified expression: The minimized expression from the K-map is: $F(P, Q, R, S) = P'S' + QR'$

Final minimized Boolean expression:

$F(P, Q, R, S) = P'S' + QR'$

Would you like to see the K-map solution or any further details?

Here are 5 related questions:

1. How do you convert between minterms and maxterms?
2. What is the significance of Karnaugh Maps in Boolean minimization?
3. How would the function change if the variables increased to 5?
4. How do POS and SOP forms relate to each other in Boolean algebra?
5. Can you explain the Quine-McCluskey method for minimization?

Tip: When minimizing Boolean functions, always check for common factors that can be grouped together using Karnaugh maps or algebraic simplifications to reduce complexity.