Math Problem Statement
Minimize the following Boolean function F (P, Q, R, S) = π (3, 5, 7, 8, 10, 11, 12, 13) to PoS form.
Solution
To minimize the given Boolean function to the Product of Sums (PoS) form, we'll follow these steps:
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List the minterms: First, convert the maxterm indices to the minterms that are missing from the range (0 to 15).
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Group the missing minterms: These missing minterms will help us identify the minterms that should be 1 in the Truth Table.
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Karnaugh Map (K-map) analysis: Place the 0s (from the given indices) on the K-map to find simplified sum terms.
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Find the simplified maxterms from the K-map to obtain the PoS expression.
Step-by-step Solution:
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Convert maxterms to minterms:
- Maxterms given:
- Minterms are all terms from 0 to 15 not listed above, which are:
.
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Create the K-map and place 0s for the given maxterms:
- 2-variable map with P and Q as the row variables and R and S as the column variables.
PQ\RS | 00 | 01 | 11 | 10 |
---|---|---|---|---|
00 | 1 | 1 | 0 | 0 |
01 | 1 | 0 | 0 | 1 |
11 | 0 | 0 | 0 | 1 |
10 | 0 | 1 | 1 | 0 |
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Identify groups of 0s and derive the maxterms from the map. The grouping will help simplify the expression:
- Group 1: Maxterms that cover columns RS = 00 → (P + R)
- Group 2: Row 01 with column RS = 11 →
- Group 3: RS = 10, PQ = 11 and PQ = 10 → (Q + R)
4. Simplified PoS: So, the minimized function in Product of Sum form is:
Do you need further clarifications?
Here are some further questions for exploring the concept:
- What is the meaning of maxterm in Boolean functions?
- How do minterms and maxterms relate?
- Can you create a truth table for the simplified PoS?
- How is the grouping performed in the Karnaugh map?
- Why PoS forms are useful in digital circuits?
Tip: Always check your simplified result by creating truth tables to verify logic validity!
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Math Problem Analysis
Mathematical Concepts
Boolean Algebra
Karnaugh Map (K-map)
Product of Sums (PoS)
Formulas
PoS Simplification using K-map
Theorems
Karnaugh Map Grouping Theorem
Suitable Grade Level
Grades 11-12, Undergraduate
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