Math Problem Statement

Expand (1 - x)/(1 + x) in ascending powers of x up to and including the term in x^2. State the set of values of x for which the series expansion is valid. Find an approximation to the fourth root of 19/21, in the form p/q, where p and q are positive integers with no common factors.

Solution

Let's work through the three parts of this problem.

(i) Expand (1x1+x)n\left( \frac{1 - x}{1 + x} \right)^n in ascending powers of xx up to and including the term in x2x^2.

We begin by expressing (1x1+x)n\left( \frac{1 - x}{1 + x} \right)^n as a binomial series. Start by simplifying:

(1x1+x)n=(12x+x2)n\left( \frac{1 - x}{1 + x} \right)^n = (1 - 2x + x^2)^n

Now, expand this in powers of xx up to x2x^2. The first few terms of the binomial expansion of (12x+x2)n(1 - 2x + x^2)^n are:

(12x+x2)n12nx+n(n1)2(4x2)+(1 - 2x + x^2)^n \approx 1 - 2nx + \frac{n(n-1)}{2}(4x^2) + \cdots

So, the expansion up to the term in x2x^2 is:

(12x+x2)n12nx+2n(n1)x2.(1 - 2x + x^2)^n \approx 1 - 2nx + 2n(n-1)x^2.

(ii) State the set of values of xx for which the series expansion is valid.

The expansion we used is a binomial series expansion. For a binomial series expansion of the form (1+ax)n(1 + ax)^n to be valid, we require:

ax<1.|ax| < 1.

In our case, the expression we expanded was (12x+x2)n(1 - 2x + x^2)^n. To ensure convergence of this series, we must ensure that x<1|x| < 1 for the binomial series expansion to hold.

Thus, the series expansion is valid for:

x<1.|x| < 1.

(iii) Find an approximation to the fourth root of 1921\frac{19}{21}, in the form pq\frac{p}{q}, where pp and qq are positive integers with no common factors.

To approximate the fourth root of 1921\frac{19}{21}, we need to expand (1921)1/4\left( \frac{19}{21} \right)^{1/4} using the binomial series.

First, express 1921\frac{19}{21} as:

1921=1221.\frac{19}{21} = 1 - \frac{2}{21}.

Now, we expand (1221)1/4(1 - \frac{2}{21})^{1/4} using the binomial expansion for (1+x)n(1 + x)^n, where n=14n = \frac{1}{4} and x=221x = -\frac{2}{21}:

(1221)1/41+14(221)=1142.(1 - \frac{2}{21})^{1/4} \approx 1 + \frac{1}{4} \left( -\frac{2}{21} \right) = 1 - \frac{1}{42}.

Thus, the approximation is:

(1921)1/41142=4142.\left( \frac{19}{21} \right)^{1/4} \approx 1 - \frac{1}{42} = \frac{41}{42}.

Since 4141 and 4242 have no common factors, the required approximation is:

pq=4142.\frac{p}{q} = \frac{41}{42}.


Do you want any further details or have any questions about this? Here are some related questions:

  1. How does the binomial expansion change when higher-order terms are included?
  2. Can you apply the binomial series expansion to complex numbers?
  3. What other methods can be used to approximate roots of fractions like 1921\frac{19}{21}?
  4. Why is the binomial expansion restricted to certain values of xx?
  5. How do you derive higher-order approximations for roots like 1921\frac{19}{21}?

Tip: When expanding a binomial expression, always ensure the series converges by checking the domain of the variable involved (e.g., ensuring x<1|x| < 1 in certain cases).

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Math Problem Analysis

Mathematical Concepts

Binomial Expansion
Series Expansion
Root Approximation

Formulas

Binomial Expansion: (1 + x)^n ≈ 1 + nx + (n(n-1)/2)x^2 + ...
Root Approximation: (1 - x)^n ≈ 1 - nx + (n(n-1)/2)x^2 + ...

Theorems

Binomial Series Theorem

Suitable Grade Level

High School (Grades 11-12)