Math Problem Statement

expand (1+x^2)^-1 and (1-x)^-1 up to and including the term x^3 and determine all values of x for which each of the expansions converge

Solution

We need to expand the two given functions using the binomial series expansion up to the x3x^3 term and also determine the radius of convergence for each series.

1. Expansion of (1+x2)1(1 + x^2)^{-1}:

We use the binomial expansion formula for (1+u)n(1 + u)^n, which is given by:

(1+u)n=1+nu+n(n1)2!u2+n(n1)(n2)3!u3+(1 + u)^n = 1 + nu + \frac{n(n-1)}{2!}u^2 + \frac{n(n-1)(n-2)}{3!}u^3 + \cdots

For (1+x2)1(1 + x^2)^{-1}, we have u=x2u = x^2 and n=1n = -1. Substituting these values into the binomial expansion:

(1+x2)1=1+(1)x2+(1)(2)2!x4+(1)(2)(3)3!x6+(1 + x^2)^{-1} = 1 + (-1)x^2 + \frac{(-1)(-2)}{2!}x^4 + \frac{(-1)(-2)(-3)}{3!}x^6 + \cdots

Now, let's expand up to and including the x3x^3 term:

(1+x2)1=1x2+(1 + x^2)^{-1} = 1 - x^2 + \cdots

Thus, the expansion of (1+x2)1(1 + x^2)^{-1} up to the x3x^3 term is:

1x2+O(x4)1 - x^2 + O(x^4)

Radius of Convergence for (1+x2)1(1 + x^2)^{-1}:

The binomial series (1+u)n(1 + u)^n converges when u<1|u| < 1. In this case, u=x2u = x^2, so the series converges when:

x2<1x<1|x^2| < 1 \quad \Rightarrow \quad |x| < 1

Thus, the series for (1+x2)1(1 + x^2)^{-1} converges for x<1|x| < 1.


2. Expansion of (1x)1(1 - x)^{-1}:

Now we consider the binomial expansion for (1x)1(1 - x)^{-1}. Using the same binomial expansion formula with u=xu = -x and n=1n = -1, we get:

(1x)1=1+(1)(x)+(1)(2)2!(x)2+(1)(2)(3)3!(x)3+(1 - x)^{-1} = 1 + (-1)(-x) + \frac{(-1)(-2)}{2!}(-x)^2 + \frac{(-1)(-2)(-3)}{3!}(-x)^3 + \cdots

Expanding up to and including the x3x^3 term:

(1x)1=1+x+22x2+66x3+O(x4)(1 - x)^{-1} = 1 + x + \frac{2}{2}x^2 + \frac{6}{6}x^3 + O(x^4)

Thus, the expansion of (1x)1(1 - x)^{-1} up to the x3x^3 term is:

1+x+x2+x3+O(x4)1 + x + x^2 + x^3 + O(x^4)

Radius of Convergence for (1x)1(1 - x)^{-1}:

For (1x)1(1 - x)^{-1}, the series converges when x<1|x| < 1, since this is a standard geometric series with the form 11x\frac{1}{1 - x}, which converges for x<1|x| < 1.


Summary:

  1. The expansion of (1+x2)1(1 + x^2)^{-1} up to x3x^3 is:

1x2+O(x4)1 - x^2 + O(x^4)

The series converges for x<1|x| < 1.

  1. The expansion of (1x)1(1 - x)^{-1} up to x3x^3 is:

1+x+x2+x3+O(x4)1 + x + x^2 + x^3 + O(x^4)

The series converges for x<1|x| < 1.


Would you like to explore more about binomial expansions or the convergence of series? Here are some related questions:

  1. How does the binomial expansion work for non-integer exponents?
  2. What is the general form of the binomial series for arbitrary nn?
  3. How can the binomial expansion be applied to functions other than polynomials, such as trigonometric or exponential functions?
  4. What happens when the expansion is carried out beyond the x3x^3 term?
  5. How do we apply the binomial expansion to functions of the form (1+axk)n(1 + ax^k)^n?

Tip: The radius of convergence of a binomial series expansion is crucial in determining where the approximation holds true; outside this radius, the series may not provide accurate results.

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Math Problem Analysis

Mathematical Concepts

Binomial Expansion
Convergence of Series
Series Approximation

Formulas

(1 + u)^n = 1 + nu + (n(n-1)/2!)u^2 + (n(n-1)(n-2)/3!)u^3 + ...
(1 + x^2)^-1 = 1 - x^2 + O(x^4)
(1 - x)^-1 = 1 + x + x^2 + x^3 + O(x^4)

Theorems

Radius of Convergence of a Binomial Series

Suitable Grade Level

Grades 11-12