Math Problem Statement

Suppose that 60% of international students and 50% of local students in a university prefer online format for office hours. A group of 20 students in the university, including 12 international students and 8 local students were asked their preferred format for office hours. A response is randomly picked from the group and is in-person. What is the probability that the response is from a local student?

Solution

We can solve this problem using Bayes' Theorem, which helps find the probability of an event given that another event has occurred.

Let's define the events:

  • AA: The event that the student is local.
  • BB: The event that the response is in-person.

We want to find the conditional probability P(AB)P(A|B), the probability that the student is local given that their response is in-person. Using Bayes' Theorem:

P(AB)=P(BA)P(A)P(B)P(A|B) = \frac{P(B|A) \cdot P(A)}{P(B)}

Where:

  • P(A)P(A) is the prior probability that the student is local.
  • P(BA)P(B|A) is the probability that a local student prefers in-person format.
  • P(B)P(B) is the total probability that a randomly chosen student prefers in-person format (whether local or international).

Step 1: Calculate P(A)P(A)

The group consists of 12 international students and 8 local students, so: P(A)=820=0.4P(A) = \frac{8}{20} = 0.4

Step 2: Calculate P(BA)P(B|A)

We know that 50% of local students prefer online format, so 50% prefer in-person format. Thus: P(BA)=0.5P(B|A) = 0.5

Step 3: Calculate P(B)P(B)

We need to find the total probability that a student prefers in-person format, which is the sum of the probabilities for international and local students. Let:

  • P(Intl)P(\text{Intl}) represent the event that a student is international.
  • P(BIntl)P(B|\text{Intl}) is the probability that an international student prefers in-person format.

We know: P(Intl)=1220=0.6P(\text{Intl}) = \frac{12}{20} = 0.6 P(BIntl)=10.6=0.4P(B|\text{Intl}) = 1 - 0.6 = 0.4

Now, using the law of total probability: P(B)=P(BA)P(A)+P(BIntl)P(Intl)P(B) = P(B|A) \cdot P(A) + P(B|\text{Intl}) \cdot P(\text{Intl}) P(B)=(0.5×0.4)+(0.4×0.6)=0.2+0.24=0.44P(B) = (0.5 \times 0.4) + (0.4 \times 0.6) = 0.2 + 0.24 = 0.44

Step 4: Apply Bayes' Theorem

Now we can apply Bayes' Theorem: P(AB)=P(BA)P(A)P(B)=0.5×0.40.44=0.20.440.4545P(A|B) = \frac{P(B|A) \cdot P(A)}{P(B)} = \frac{0.5 \times 0.4}{0.44} = \frac{0.2}{0.44} \approx 0.4545

Thus, the probability that the response is from a local student given that it is in-person is approximately 45.45%.


Would you like more details or have any questions? Here are five related questions to explore the topic further:

  1. How would the result change if a higher percentage of international students preferred in-person office hours?
  2. What if the group of students had a different proportion of local and international students?
  3. How does the use of Bayes' Theorem help in decision-making in real-world problems?
  4. What if the percentage of local students who prefer online format changed to 60%? How would that impact the result?
  5. How would you calculate the probability if you knew the exact number of students who prefer in-person office hours?

Tip: Bayes' Theorem is useful in various real-world applications like medical testing, spam filtering, and decision-making under uncertainty.

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Math Problem Analysis

Mathematical Concepts

Probability
Bayes' Theorem
Conditional Probability
Law of Total Probability

Formulas

Bayes' Theorem: P(A|B) = (P(B|A) * P(A)) / P(B)
Law of Total Probability: P(B) = P(B|A) * P(A) + P(B|Intl) * P(Intl)

Theorems

Bayes' Theorem
Law of Total Probability

Suitable Grade Level

Grades 11-12