What is the value of the variable z after the following lines of code are executed?

                        int z = 5;

                        z = z * 3;

                        z = z + 1

Group of answer choices

2

16

4

15

either it’s undefined, or an error would be generated

Let’s analyze the code step by step:

1. **`int z = 5;`**  
   - The variable `z` is initialized with the value **5**.

2. **`z = z * 3;`**  
   - Now, `z` is updated:  
     \( z = 5 \times 3 = 15 \)

3. **`z = z + 1;`**  
   - Now, `z` is updated again:  
     \( z = 15 + 1 = 16 \)

### Final value of `z` = **16**

So, the correct answer is:

**16**

### Answer:  
**16**

Would you like to ask more about this problem, such as variations or other related concepts?  

Here are five questions related to variable operations:  
1. What is the difference between `z++` and `z = z + 1`?  
2. How does operator precedence work in arithmetic expressions?  
3. What happens if you use `float` instead of `int` in this code?  
4. How would a division operation behave in a similar sequence of statements?  
5. What happens if `z` is declared but not initialized?  

**Tip:** When using variables, always remember to initialize them before performing operations to avoid undefined behavior.

What is the value of the variable z after the following lines of code are executed?

int z = 5;
z = z * 3;
z = z + 1;

Group of answer choices:
2
16
4
15
either it’s undefined, or an error would be generated

Discover how to find the value of a variable after a sequence of arithmetic operations. This example demonstrates basic algebra concepts, including variable assignment and order of operations. Suitable for Grades 6-8.

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