The image you provided contains several algebraic expressions that require substitution of given values. Let's go through each of them step by step:

Problem 2) $k - 4d$

• Given: $k = 5$ and $d = 6$
• Substitution: $5 - 4(6)$
• Calculation: $5 - 24 = -19$
• Final Answer: $-19$

Problem 3) $-5(3z - 2k)$

• Given: $k = -4$ and $z = 5$
• Substitution: $-5(3(5) - 2(-4))$
• Calculation: $-5(15 + 8) = -5(23) = -115$
• Final Answer: $-115$

Problem 4) $-6 + \frac{5}{4} - 8w$

• Given: $s = 8$ and $w = -4$
• Substitution: $-6 + \frac{5}{4} - 8(-4)$
• Calculation: $-6 + \frac{5}{4} + 32$ $-6 + 32 + \frac{5}{4} = 26 + \frac{5}{4} = 26 + 1.25 = 27.25$
• Final Answer: $27.25$

Would you like any further details on these solutions, or do you have any other questions?

Here are five related questions to practice:

1. What is the result of substituting $k = 7$ and $d = 2$ into the expression $k - 4d$?
2. If $z = 3$ and $k = 2$, what is the value of $-5(3z - 2k)$?
3. Solve $-6 + \frac{3}{2} - 7w$ when $w = 5$.
4. What happens to the expression $k - 4d$ if $d$ is doubled?
5. How would the answer to $-5(3z - 2k)$ change if both $z$ and $k$ are negative?

Tip: When dealing with algebraic expressions, always remember to follow the order of operations (PEMDAS: Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).