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This problem asks to find the area of a square, given some geometric conditions. Here's a rough translation and interpretation of the problem:

- The line \( L: y = 2x - 1 \) passes through one of the vertices of the square.
- Another vertex of the square is at \( A(3, 0) \).
- The task is to determine the area of the square.

### Steps to Solve:

1. **Vertex Location**: We know one vertex is at \( A(3, 0) \). The line equation \( y = 2x - 1 \) provides the slope of one of the sides (or diagonals) of the square.

2. **

One of the vertices of a square lies on the line L: y = 2x - 1. Another vertex is located at A(3, 0). Find the area of the square.

Solve a geometry problem involving a square with one vertex on the line y = 2x - 1 and another at point A(3, 0). Use analytic geometry to find the area of the square. Suitable for high school students in Grades 9-11.

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