18. The area of a triangle whose sides are respectively 3, 4 and 5 (in cm) is: एक त्रिभुज का क्षेत्रफल जिसकी भुजाएँ क्रमशः 3, 4 और 5 (सेमी) हैं:

Ops:

A. 6 cm2

B. 60 cm2

C. 30 cm2

D. 10 cm2.

The triangle with sides 3 cm, 4 cm, and 5 cm is a right-angled triangle (since \(3^2 + 4^2 = 5^2\)). In a right-angled triangle, the area can be calculated using the formula:

\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]

Here, the base is 3 cm, and the height is 4 cm. Plugging in these values:

\[
\text{Area} = \frac{1}{2} \times 3 \times 4 = \frac{1}{2} \times 12 = 6 \, \text{cm}^2
\]

Thus, the area of the triangle is:

**A. 6 cm²**

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Would you like further details or have any questions? Here are some related problems to consider:

1. What is the area of a right-angled triangle with sides 6 cm, 8 cm, and 10 cm?
2. How do you find the area of a triangle if the height is not given?
3. What is Heron's formula, and when is it used?
4. Can you prove that a triangle with sides 5 cm, 12 cm, and 13 cm is a right-angled triangle?
5. What is the perimeter of a triangle with sides 7 cm, 24 cm, and 25 cm?

**Tip:** Always check if the given sides satisfy the Pythagorean theorem to identify right-angled triangles quickly.

The area of a triangle whose sides are respectively 3, 4, and 5 (in cm) is: एक त्रिभुज का क्षेत्रफल जिसकी भुजाएँ क्रमशः 3, 4 और 5 (सेमी) हैं:

Learn how to find the area of a right-angled triangle with sides 3 cm, 4 cm, and 5 cm. This problem explores the use of the Pythagorean theorem and area formula for triangles. Suitable for students in Grades 6-8.

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