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This is a right-angled triangle with a base of 8 cm and a height of 6 cm. The area \( A \) of a triangle can be calculated using the formula:

\[
A = \frac{1}{2} \times \text{base} \times \text{height}
\]

Substitute the given values:

\[
A = \frac{1}{2} \times 8 \, \text{cm} \times 6 \, \text{cm} = \frac{1}{2} \times 48 = 24 \, \text{cm}^2
\]

Thus, the area of the triangle is **24 cm²**.

Would you like further details or have any questions? Here are 5 related questions to explore further:

1. How would you calculate the perimeter of this triangle?
2. How would the area change if the height was doubled?
3. What is the length of the hypotenuse using the Pythagorean theorem?
4. How do you find the area of an equilateral triangle?
5. What would the area be if both the base and height were halved?

**Tip:** For any right-angled triangle, knowing two sides allows you to calculate the third side using the Pythagorean theorem.

Work out the area of this triangle with a base of 8 cm and a height of 6 cm.

Learn how to find the area of a right-angled triangle with a base of 8 cm and a height of 6 cm. This problem covers key geometry concepts and is suitable for students in Grades 6-8.

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