Math Problem Statement

The base of an isosceles triangle is parallel to the x-axis and has both endpoints on the parabola y = x(10 − x). Find the area of the triangle if its vertex belongs to the x-axis and the length of its base is 8.

Solution

Let's break down the problem step by step.

Step 1: Equation of the Parabola

The given parabola is y=x(10x)y = x(10 - x), which can be rewritten as: y=10xx2.y = 10x - x^2. This parabola opens downward, and its vertex occurs at x=5x = 5 (the midpoint of 00 and 1010, the x-intercepts). The endpoints of the base of the isosceles triangle are on this parabola.

Step 2: Identify the Base Endpoints

We are told the base of the isosceles triangle is parallel to the x-axis, and its length is 8 units. This means the x-coordinates of the endpoints of the base must be symmetric around the midpoint of the base.

Let the x-coordinates of the endpoints of the base be x1x_1 and x2x_2. Since the length of the base is 8, we know that: x2x1=8.|x_2 - x_1| = 8. For symmetry, let the midpoint be at x=5x = 5, so: x1=54=1andx2=5+4=9.x_1 = 5 - 4 = 1 \quad \text{and} \quad x_2 = 5 + 4 = 9.

Step 3: Find the y-Coordinates of the Base Endpoints

We now substitute x1=1x_1 = 1 and x2=9x_2 = 9 into the equation of the parabola y=10xx2y = 10x - x^2 to find the y-coordinates of the endpoints:

For x1=1x_1 = 1: y1=10(1)(1)2=101=9.y_1 = 10(1) - (1)^2 = 10 - 1 = 9.

For x2=9x_2 = 9: y2=10(9)(9)2=9081=9.y_2 = 10(9) - (9)^2 = 90 - 81 = 9.

So, the coordinates of the endpoints of the base are (1,9)(1, 9) and (9,9)(9, 9), and the base lies at y=9y = 9.

Step 4: Find the Area of the Triangle

The vertex of the triangle lies on the x-axis, so the vertex has coordinates (5,0)(5, 0) because the vertex is directly below the midpoint of the base.

The area of a triangle is given by the formula: Area=12×base×height.\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}. Here, the base of the triangle is the distance between the points (1,9)(1, 9) and (9,9)(9, 9), which is 8 units. The height of the triangle is the vertical distance between the x-axis and the base, which is 9 units.

Thus, the area is: Area=12×8×9=36.\text{Area} = \frac{1}{2} \times 8 \times 9 = 36.

Final Answer:

The area of the triangle is 36\boxed{36}.

Would you like further details or have any questions?

Related Questions:

  1. How do you find the coordinates of the vertex of a parabola from its equation?
  2. What is the formula for the area of a triangle in terms of its base and height?
  3. How can you determine the symmetry of a parabola from its equation?
  4. What is the significance of the midpoint when dealing with symmetric shapes like isosceles triangles?
  5. How can the height of a triangle be related to the distance between points on a curve?

Tip: When working with geometric problems involving curves, always start by identifying key points (like vertex, base endpoints) and use symmetry to simplify calculations.

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Math Problem Analysis

Mathematical Concepts

Coordinate Geometry
Parabolas
Triangles and Area
Symmetry in Geometry

Formulas

Equation of a parabola: y = ax^2 + bx + c
Midpoint formula: (x1 + x2) / 2
Distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2)
Area of a triangle: (1/2) × base × height

Theorems

Symmetry of parabolas around their vertex
Relationship between geometric figures and algebraic curves

Suitable Grade Level

Grades 9-11