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To solve the problem and find the area of the isosceles triangle \( \triangle ABC \), I will extract the coordinates from the graph.

The vertices of the triangle appear to be approximately:
- \( A(0, 0) \)
- \( B(4, 0) \)
- \( C(0, 3) \)

### Steps:
1. **Base \( AB \):** The length of \( AB \) is 4 units.
2. **Height \( AC \):** The length of \( AC \) is 3 units.

### Area of \( \triangle ABC \):
\[
\text{Area} = \frac{1}{2} \times \text{Base} \times \text{Height} = \frac{1}{2} \times 4 \times 3 = 6 \text{ square units}
\]

The area of \( \triangle ABC \) is \( 6 \) square units.

Would you like any further details or have any questions?

Here are 5 related questions to consider:
1. How do you determine the lengths of the sides of a triangle given the coordinates?
2. What are the characteristics of an isosceles triangle?
3. How can you calculate the area of a triangle using different methods (e.g., Heron's formula)?
4. How would the area change if the triangle were not isosceles?
5. Can you find the perimeter of this triangle?

**Tip:** When dealing with geometric figures on a coordinate plane, always identify and confirm the exact coordinates of the vertices before proceeding with calculations.

Learn how to find the area of an isosceles triangle given its vertices on a coordinate plane. This problem uses basic geometric concepts, including calculating the base and height of the triangle. Suitable for students in Grades 6-8.

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