Math Problem Statement
Solution
The problem involves sequences and their properties. I'll guide you step by step through each part.
1. Sequence defined as and .
(a) Show that :
- Base case (): , so is true.
- Inductive step: Assume . Then:
- implies and .
- implies and .
- Thus, , completing the induction.
(b) Let be the positive root of . Show :
The equation gives (positive root).
- Note that by substituting into the sequence's recurrence relation.
- Let . Then:
- Using a common denominator: The denominator is positive, so: Since , we have .
(c) Show :
- From part (b), is decreasing.
- Initially, .
- By induction, the bound is derived based on recursive multiplication of , which is less than 1.
(d) Show converges:
- From part (c), as .
- Hence, .
2. Sequence defined as , .
(a) Show :
- , and , so by induction.
(b) Show :
- Using the recursive relations and substituting , simplify the relation.
(c) Show :
- From the recurrence relations, derive the inequality by analyzing the growth of relative to .
(d) Find :
- Use the convergence of and the behavior of to evaluate the limit.
Let me know which specific part you'd like detailed further! Here are 5 related questions:
- What are the general properties of bounded monotonic sequences?
- How is the golden ratio derived from the quadratic equation?
- Why does the recurrence relation ensure convergence of ?
- Can diverge if converges to a nonzero limit?
- How can the techniques here be applied to other sequences?
Tip: Always verify the monotonicity and boundedness of sequences when proving convergence!
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Math Problem Analysis
Mathematical Concepts
Sequences and recurrence relations
Convergence of sequences
Bounded and monotonic sequences
Quadratic equations
Formulas
Recurrence relation: Un+1 = 1 / (1 + Un)
Quadratic equation: x² + x - 1 = 0
Positive root of the quadratic equation: φ = (-1 + sqrt(5)) / 2
Theorems
Convergence theorem for monotonic bounded sequences
Properties of the golden ratio φ derived from x² + x - 1 = 0
Suitable Grade Level
Undergraduate level or advanced high school (Grades 11-12)