https://file.aiquickdraw.com/mathbot/file/1729598803580p3qeoiw4.jpg

Let's go step by step in solving the mathematical tasks outlined in the image.

### Given Function:
The function is defined as \( f(x) = x - 2\sqrt{x} + 1 \), with the domain \( x \in \mathbb{R}^+ \).

### 1) Verifier que \( f(x) = (\sqrt{x} - 1)^2 \)
We need to verify that the given expression for \( f(x) \) can be rewritten as \( (\sqrt{x} - 1)^2 \).

- Starting with \( f(x) = x - 2\sqrt{x} + 1 \):
  \[
  (\sqrt{x} - 1)^2 = (\sqrt{x})^2 - 2(\sqrt{x})(1) + (1)^2 = x - 2\sqrt{x} + 1.
  \]
- Thus, \( f(x) = (\sqrt{x} - 1)^2 \), which is verified.

### 2) Calculer \( \lim_{x \to +\infty} f(x) \)

To calculate this limit:
\[
f(x) = x - 2\sqrt{x} + 1.
\]

As \( x \to +\infty \):
- \( x \to +\infty \),
- \( \sqrt{x} \to +\infty \), so \( -2\sqrt{x} \to -\infty \).

Thus, the behavior of \( f(x) \) at infinity is dominated by \( x \), so:
\[
\lim_{x \to +\infty} f(x) = +\infty.
\]

### 3) Continuité de la fonction \( f \) sur \( \mathbb{R}^+ \)

Since the function is composed of basic continuous functions (polynomials and square roots), and there is no discontinuity in \( f(x) = x - 2\sqrt{x} + 1 \) for \( x \geq 0 \), the function is continuous on \( \mathbb{R}^+ \).

### 4) Dérivabilité de la fonction à droite de 0 et interprétation géométrique

To check the differentiability, we first calculate the derivative of \( f(x) \) for \( x > 0 \).

\[
f'(x) = \frac{d}{dx}(x - 2\sqrt{x} + 1) = 1 - \frac{2}{2\sqrt{x}} = 1 - \frac{1}{\sqrt{x}}.
\]

Next, evaluate the right-hand derivative at \( x = 0 \) using the limit:
\[
f'_+(0) = \lim_{x \to 0^+} \frac{f(x) - f(0)}{x - 0} = \lim_{x \to 0^+} \frac{(x - 2\sqrt{x} + 1) - 1}{x} = \lim_{x \to 0^+} \frac{x - 2\sqrt{x}}{x}.
\]

Simplifying:
\[
f'_+(0) = \lim_{x \to 0^+} \left(1 - \frac{2}{\sqrt{x}}\right).
\]

As \( x \to 0^+ \), \( \frac{2}{\sqrt{x}} \to \infty \), so:
\[
f'_+(0) = -\infty.
\]
Thus, the function is not differentiable at 0.

---

The remaining questions involve further exploration of the function, its variations, tangents, and inverse. Would you like me to continue solving them or explain any part in more detail?

Here are 5 related questions for deeper understanding:
1. How do we analyze the global behavior of \( f(x) \) from a graph perspective?
2. Can the non-differentiability at 0 be interpreted geometrically?
3. What methods can we use to find the equation of a tangent line at any given point?
4. How can we determine if \( f \) is invertible on a specific interval?
5. What are the conditions under which a function's inverse is differentiable?

**Tip:** For functions with square roots, always check for potential issues in differentiability and domain boundaries.

Soit f la fonction définie sur IR+ par : f(x) = x - 2√x + 1

This problem explores the function f(x) = x - 2√x + 1, including verifying expressions, calculating limits as x approaches infinity, and studying the function's continuity and differentiability. A detailed step-by-step solution is provided, covering key calculus concepts.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation