Math Problem Statement

Исследовать функцию f(x) = x - ln(x + 1) и построить её график.

Solution

The task is to analyze the function f(x)=xln(x+1)f(x) = x - \ln(x+1) and construct its graph. Let's break this down step by step:


Step 1: Domain of the function

The logarithmic term ln(x+1)\ln(x+1) is defined when x+1>0x+1 > 0, so: x>1x > -1 Thus, the domain of the function is x(1,+)x \in (-1, +\infty).


Step 2: First derivative for monotonicity and critical points

The derivative of f(x)f(x) is: f(x)=11x+1f'(x) = 1 - \frac{1}{x+1} Simplify: f(x)=xx+1f'(x) = \frac{x}{x+1}

  • f(x)=0f'(x) = 0 when x=0x = 0. This is a critical point.
  • Analyze the sign of f(x)f'(x):
    • For x(1,0)x \in (-1, 0), f(x)<0f'(x) < 0 (function is decreasing).
    • For x(0,+)x \in (0, +\infty), f(x)>0f'(x) > 0 (function is increasing).

Thus, x=0x = 0 is a local minimum.


Step 3: Second derivative for concavity

The second derivative is: f(x)=ddx(xx+1)f''(x) = \frac{d}{dx} \left( \frac{x}{x+1} \right) Using the quotient rule: f(x)=(1)(x+1)x(1)(x+1)2=1(x+1)2f''(x) = \frac{(1)(x+1) - x(1)}{(x+1)^2} = \frac{1}{(x+1)^2}

  • f(x)>0f''(x) > 0 for all x>1x > -1, meaning the function is concave up everywhere in its domain.

Step 4: Behavior at boundaries

  1. As x1+x \to -1^+, ln(x+1)\ln(x+1) \to -\infty, so f(x)+f(x) \to +\infty.
  2. As x+x \to +\infty, ln(x+1)\ln(x+1) grows slower than xx, so f(x)+f(x) \to +\infty.

Step 5: Key points

Evaluate the function at some points:

  • At x=0x = 0: f(0)=0ln(1)=0f(0) = 0 - \ln(1) = 0.
  • At x=1x = 1: f(1)=1ln(2)10.693=0.307f(1) = 1 - \ln(2) \approx 1 - 0.693 = 0.307.
  • At x=2x = 2: f(2)=2ln(3)21.099=0.901f(2) = 2 - \ln(3) \approx 2 - 1.099 = 0.901.

Step 6: Graph sketch

  1. The function decreases for x(1,0)x \in (-1, 0) and has a local minimum at x=0x = 0.
  2. It increases for x(0,+)x \in (0, +\infty).
  3. The graph is concave up everywhere.
  4. Asymptotic behavior near x=1x = -1 and as x+x \to +\infty.

Would you like me to generate the graph for this function? Let me know if you’d like any step explained further or if you have specific questions!

Related Questions:

  1. What is the role of concavity in determining the shape of the graph?
  2. Can we determine the asymptotes of f(x)f(x) more formally?
  3. How do logarithmic functions influence domain restrictions?
  4. What happens if we shift the function by adding a constant to f(x)f(x)?
  5. How would you find the inverse of f(x)f(x) if it exists?

Tip: Always check the domain of a logarithmic function before proceeding with analysis!

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Math Problem Analysis

Mathematical Concepts

Calculus
Logarithmic Functions
Derivatives
Concavity

Formulas

f'(x) = 1 - 1/(x+1)
f''(x) = 1/(x+1)^2

Theorems

Quotient Rule for Derivatives
Properties of Logarithmic Functions

Suitable Grade Level

Undergraduate Calculus or Advanced High School