an object is dropped. what’s its acceleration after 1,2,3 secs

When an object is dropped in free fall near the Earth's surface, it accelerates due to gravity. The acceleration due to gravity is constant and denoted by **\( g \)**, with a value of approximately **\( 9.8 \, \text{m/s}^2 \)**.

The acceleration remains constant during the entire free-fall motion. Therefore, after 1, 2, 3, or any number of seconds, the object's acceleration is:

\[
a = g = 9.8 \, \text{m/s}^2
\]

Thus, the acceleration at:
- 1 second = **\( 9.8 \, \text{m/s}^2 \)**
- 2 seconds = **\( 9.8 \, \text{m/s}^2 \)**
- 3 seconds = **\( 9.8 \, \text{m/s}^2 \)**

Since gravity is constant in free fall (ignoring air resistance), this value remains unchanged.

Would you like more details on the velocity or displacement of the object at those times?

Here are 5 related questions to consider:
1. What is the velocity of the object after 1, 2, and 3 seconds?
2. How far does the object fall in 1, 2, and 3 seconds?
3. What happens to the acceleration if air resistance is considered?
4. How does mass affect free fall acceleration?
5. How would the acceleration change if the object were on the Moon?

**Tip**: The velocity of an object in free fall increases linearly with time while the acceleration remains constant.

An object is dropped. What’s its acceleration after 1, 2, 3 secs?

Learn how gravitational acceleration remains constant at 9.8 m/s² when an object is dropped in free fall. This problem explains kinematics concepts and provides a detailed explanation of acceleration at 1, 2, and 3 seconds. Ideal for high school students.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation