The problem describes how the distance an object falls increases as time progresses, following a constant acceleration due to gravity. From the given dataThe problem describes how the distance an object falls increases as time progresses, following a constant acceleration due to gravity. From the given

• In the first second, the object falls 16 feet.
• In the second second, it falls 48 feet.
• In the third second, it falls 80 feet.

Notice the difference between each second is 32 feet, indicating a linear pattern of acceleration.

(ii) How many feet would an object fall in the sixth second?

From the pattern:

• 1st second: 16 feet
• 2nd second: 48 feet
• 3rd second: 80 feet
• 4th second: $80 + 32 = 112$ feet
• 5th second: $112 + 32 = 144$ feet
• 6th second: $144 + 32 = 176$ feet

Thus, in the sixth second, the object falls 176 feet.

(iii) How many feet would an object fall in the eighth second?

Continuing the pattern:

• 6th second: 176 feet
• 7th second: $176 + 32 = 208$ feet
• 8th second: $208 + 32 = 240$ feet

Thus, in the eighth second, the object falls 240 feet.

Would you like more details on this calculation or have any further questions?

Here are 5 related questions to explore further:

1. How can we generalize the distance an object falls in any given second?
2. What is the total distance fallen after 8 seconds?
3. How does gravity affect the speed and acceleration of a falling object?
4. What mathematical formula represents the distance fallen after $n$ seconds?
5. Can air resistance significantly affect the distance fallen?

Tip: The distance an object falls due to gravity increases quadratically over time because of constant acceleration.