Math Problem Statement

Determine whether each statement is true or false

Determine whether each statement is true or false for the object falling from a height of 80 m under gravity with g = 10 m/s².

Solution

The problem involves an object in free fall from a height of 80 meters with g=10m/s2g = 10 \, \text{m/s}^2. Let’s analyze the provided statements one by one:


Equations Used:

  1. Distance fallen in time tt:
    s=12gt2s = \frac{1}{2} g t^2
  2. Velocity at time tt:
    v=gtv = g t
  3. Total time to fall:
    The total time TT to hit the ground is found from:
    stotal=12gT2where stotal=80ms_{\text{total}} = \frac{1}{2} g T^2 \quad \text{where } s_{\text{total}} = 80 \, \text{m} Solving for TT:
    T=2×8010=16=4seconds.T = \sqrt{\frac{2 \times 80}{10}} = \sqrt{16} = 4 \, \text{seconds.}

Analysis of Statements:

(a) Distance fallen in the first 1 second:

Using s=12gt2s = \frac{1}{2} g t^2:
s=12×10×(1)2=5meters.s = \frac{1}{2} \times 10 \times (1)^2 = 5 \, \text{meters.}
True.

(b) Distance fallen in the last second:

In the last second, we consider the total distance traveled by the object minus the distance traveled in the first T1T-1 seconds:
slast second=stotal(12g(T1)2)s_{\text{last second}} = s_{\text{total}} - \left(\frac{1}{2} g (T-1)^2\right)
Substituting T=4T = 4:
slast second=8012×10×(41)2=8012×10×9=8045=35meters.s_{\text{last second}} = 80 - \frac{1}{2} \times 10 \times (4-1)^2 = 80 - \frac{1}{2} \times 10 \times 9 = 80 - 45 = 35 \, \text{meters.}
True.

(c) Velocity after 2 seconds:

Using v=gtv = g t:
v=10×2=20m/s.v = 10 \times 2 = 20 \, \text{m/s.}
However, the statement claims 10 m/s, which is incorrect.
False.

(d) Velocity upon hitting the ground:

Using v=gTv = g T:
v=10×4=40m/s.v = 10 \times 4 = 40 \, \text{m/s.}
The statement claims 20 m/s, which is incorrect.
False.


Summary of Truth Values:

  • (a) True
  • (b) True
  • (c) False
  • (d) False

Would you like a detailed breakdown of any specific calculation or additional explanation?

Related Questions:

  1. How is the total time of free fall calculated using gg and height?
  2. What is the formula to determine the distance traveled in the nn-th second?
  3. How does air resistance affect free fall calculations like these?
  4. How can we derive velocity at a specific time during free fall?
  5. What would change if the object was dropped on a different planet with different gg?

Tip: When solving motion problems, always start with the basic kinematic equations and clearly define known and unknown values.

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Math Problem Analysis

Mathematical Concepts

Free Fall
Kinematics
Equations of Motion

Formulas

Distance fallen in time t: s = (1/2) * g * t²
Velocity at time t: v = g * t
Total time to fall: T = √(2h / g)
Distance fallen in nth second: s_n = u + (1/2) * g * (2n - 1)

Theorems

Laws of Motion

Suitable Grade Level

Grades 9-12