Math Problem Statement

  1. Do the following arithmetic as if these were five-bit signed representations and indicate if overflow occurs and, if so, why. Note: Remember that you want to add. So, for signed subtraction, convert the subtrahend (the number being subtracted) to its 2's complement and add it.

    a. 10110 + 01101 b. 11001 + 00101 c. 10110 - 01101 d. 11111 - 01011

Solution

When performing these arithmetic operations with five-bit signed representations, it's important to remember that:

  • In five-bit signed numbers, the first bit is the sign bit:
    • 0 = positive
    • 1 = negative
  • The range of values for five-bit signed numbers is 16-16 to +15+15.
    • Positive numbers range from 0000000000 (0) to 0111101111 (+15)
    • Negative numbers range from 1111111111 (-1) to 1000010000 (-16)

We'll convert each binary number to its decimal equivalent, perform the operations, and check for overflow. Overflow happens when the result is outside the range [16,15][-16, 15].

a) 10110+0110110110 + 01101

  1. Convert to decimal:

    • 10110=1010110 = -10 (two's complement)
    • 01101=+1301101 = +13
  2. Perform the addition: 10+13=3-10 + 13 = 3

  3. Check for overflow:

    • The result, 33, is within the valid range [16,15][-16, 15], so no overflow.

Result: 33, no overflow.

b) 11001+0010111001 + 00101

  1. Convert to decimal:

    • 11001=711001 = -7 (two's complement)
    • 00101=+500101 = +5
  2. Perform the addition: 7+5=2-7 + 5 = -2

  3. Check for overflow:

    • The result, 2-2, is within the valid range [16,15][-16, 15], so no overflow.

Result: 2-2, no overflow.

c) 101100110110110 - 01101

For subtraction, convert the subtrahend (0110101101) to its two's complement form and add it.

  1. Convert to decimal:

    • 10110=1010110 = -10 (two's complement)
    • 01101=+1301101 = +13
  2. Find two's complement of 0110101101:

    • Flip the bits: 1001010010
    • Add 1: 10011=1310011 = -13 (two's complement)
  3. Perform the addition: 10+(13)=23-10 + (-13) = -23

  4. Check for overflow:

    • The result, 23-23, is outside the valid range [16,15][-16, 15], so overflow occurs.

Result: Overflow occurs because 23-23 is out of range.

d) 111110101111111 - 01011

For subtraction, convert the subtrahend (0101101011) to its two's complement form and add it.

  1. Convert to decimal:

    • 11111=111111 = -1 (two's complement)
    • 01011=+1101011 = +11
  2. Find two's complement of 0101101011:

    • Flip the bits: 1010010100
    • Add 1: 10101=1110101 = -11 (two's complement)
  3. Perform the addition: 1+(11)=12-1 + (-11) = -12

  4. Check for overflow:

    • The result, 12-12, is within the valid range [16,15][-16, 15], so no overflow.

Result: 12-12, no overflow.


Would you like any details or further clarifications? Here are some related questions for further exploration:

  1. What are the benefits of using two's complement for signed number representation?
  2. How do you detect overflow in signed binary addition?
  3. What would happen if we used 6-bit signed numbers instead of 5-bit?
  4. Can you explain the difference between one's complement and two's complement representation?
  5. How is two's complement subtraction different from addition?

Tip: In two's complement, to negate a binary number, you simply flip the bits and add 1, making arithmetic operations like subtraction simpler!

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Math Problem Analysis

Mathematical Concepts

Binary Arithmetic
Two's Complement
Overflow Detection

Formulas

Two's Complement: Invert bits and add 1
Overflow Detection Rule: Result outside [-16, 15] in 5-bit representation

Theorems

Signed Binary Addition Theorem
Overflow in Two's Complement Arithmetic

Suitable Grade Level

Grades 10-12