Math Problem Statement

Add (-10)10 + (-12)10 using 5-bit signed 2’s complement format. Check for overflow. If the over follow happens, modify to obtain the correct result and show this result in the decimal format.

Solution

To solve the problem of adding (-10)₁₀ + (-12)₁₀ using 5-bit signed 2's complement format, we'll follow these steps:

1. Convert the decimal numbers to 5-bit signed 2's complement:

(-10)₁₀ in 5-bit 2's complement:

  1. The positive binary of 10 in 5 bits:
    • 1010=01010210_{10} = 01010_2
  2. To find the 2's complement, invert the bits and add 1:
    • Inverted: 10101210101_2
    • Add 1: 101012+1=10110210101_2 + 1 = 10110_2

So, (-10)₁₀ in 5-bit 2's complement is: (10)10=101102(-10)_{10} = 10110_2

(-12)₁₀ in 5-bit 2's complement:

  1. The positive binary of 12 in 5 bits:
    • 1210=01100212_{10} = 01100_2
  2. To find the 2's complement, invert the bits and add 1:
    • Inverted: 10011210011_2
    • Add 1: 100112+1=10100210011_2 + 1 = 10100_2

So, (-12)₁₀ in 5-bit 2's complement is: (12)10=101002(-12)_{10} = 10100_2

2. Add the two 5-bit signed numbers:

101102+10100210110_2 + 10100_2

Performing the binary addition:

& 1 & 0 & 1 & 1 & 0 \\ + & 1 & 0 & 1 & 0 & 0 \\ \hline 1 & 0 & 1 & 0 & 1 & 0 \\ \end{array}$$ Result: $$1 01010_2$$ ### 3. Check for overflow: Since this is a 5-bit system, the leftmost 1 (the 6th bit) is an overflow, meaning the sum cannot be represented correctly in 5 bits. ### 4. Correct the result: Ignoring the overflow bit, the result is: $$01010_2$$ Convert this back to decimal: $$01010_2 = 10_{10}$$ This is the **wrong result** because of the overflow. ### 5. Correct result (adjusting the sum): Since overflow occurred, we need to interpret the overflowed result differently. The sum of (-10)₁₀ + (-12)₁₀ is supposed to be: $$(-10) + (-12) = -22_{10}$$ Now, we need to represent -22 in 5-bit signed 2's complement format. However, -22 cannot be represented in 5 bits since the range of 5-bit signed 2's complement is from -16 to +15. Therefore, **it is impossible to represent the correct result (-22) in 5-bit format**. ### Conclusion: There is an overflow because the sum (-22) is out of the range for 5-bit signed numbers. The correct sum of (-10) + (-12) is: $$(-22)_{10}$$ This cannot be represented in a 5-bit signed 2's complement system. --- Would you like more details or have any further questions? ### Expanding Questions: 1. What is the range of numbers that can be represented in 5-bit signed 2's complement? 2. How do you detect overflow in binary addition of 2's complement numbers? 3. Can overflow occur when adding two positive or two negative numbers? 4. How do you extend 5-bit representation to a larger number of bits (e.g., 8-bit or 16-bit)? 5. What other ways can binary arithmetic errors manifest besides overflow? #### Tip: When detecting overflow in 2's complement addition, always check if two positive numbers give a negative result or two negative numbers give a positive result.

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Math Problem Analysis

Mathematical Concepts

Binary Arithmetic
2's Complement
Overflow Detection

Formulas

Binary Addition
2's Complement Conversion

Theorems

Overflow Detection in 2's Complement

Suitable Grade Level

Grades 10-12