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This question involves calculating the total displacement of a car that travels 35 km north and then 20 km east. The car's movement forms a right-angled triangle, with the two sides being 35 km (north) and 20 km (east). The displacement is the hypotenuse of this triangle, which can be calculated using the Pythagorean theorem.

The formula is:

\[
\text{Displacement} = \sqrt{(35^2 + 20^2)}
\]

Let me calculate that for you.The total displacement of the car, rounded to the nearest tenth, is **40.3 km**. Therefore, the correct answer is **D. 40.3 km**.

Would you like more details or have any questions?

Here are some related questions to expand on this concept:
1. How do we calculate the displacement if the car traveled in a different direction, say southeast?
2. What is the difference between distance and displacement?
3. How does the Pythagorean theorem apply to real-world scenarios involving vectors?
4. How would you calculate the car's average speed if the time of travel is given?
5. How does displacement change if the car returns to its starting point?

**Tip:** When dealing with problems involving displacement and directions, visualize the scenario on a coordinate plane to better understand the vector components.

What is the total displacement, to the nearest tenth, of a car that travels 35 km north, then 20 km east?

Learn how to calculate the total displacement of a car traveling 35 km north and 20 km east. This problem uses the Pythagorean theorem to find the total displacement of 40.3 km, suitable for students in Grades 8-10.

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